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Vilka [71]
2 years ago
10

Curt filled 120 cups with juice for the party. He placed 15 cups on each tray. He accidentally spilled 3 trays of juice. How man

y trays of juice does he still have for the party?
Mathematics
1 answer:
Romashka [77]2 years ago
3 0
30 treys left I think
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Greg plowed for 2.5 hours in the morning, 1 hour and 15 minutes in the afternoon, and 1 hour and 30 minutes in the evening. How
HACTEHA [7]

Answer:

Five hours and fifteen minutes.

Step-by-step explanation:

You add all these together and it gets five hours and fifteen minutes.

6 0
3 years ago
Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
3 years ago
Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation 7 If
Juliette [100K]

Answer:

The required constant of variation is 4 and the equation is y=4xz over w (over meaning a fraction)

I don't know if you need a explanation on how to do this, just let me know if so.

Step-by-step explanation:

7 0
2 years ago
(4.3 * 10-3)(2 x 10-2)​
FinnZ [79.3K]

<em>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</em>

<em>➷ </em>(4.3\cdot10-3)(2\cdot 10-2)<em />

<em>➷ </em>= (43 - 3)((2) (10) -2)<em />

<em>➷ </em>= 40 ((2) (10)-2)<em />

<em> ➷ </em>= 40(20 - 2)<em />

<em> ➷ </em>= (40)(18)<em />

<em> ➷ </em>= 720<em />

<em>✽</em>

<em>➶ Hope This Helps You!</em>

<em>➶ Good Luck (:</em>

<em>➶ Have A Great Day ^-^</em>

<em>↬ May ♡</em>

<em />

3 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE, THANKS! :)
Alenkasestr [34]

Answer:

Option A

Step-by-step explanation:

This is a great question!

The first thing we want to do here is to graph the system of " inequalities " -

\begin{bmatrix}2x+9y\le \:100\\ 9x+y\le \:54\end{bmatrix}

As x is ≥ 0, respectively y ≥ 0, it makes things a lot simpler, as it kind of restricts us to quadrant 1, but not entirely.

First change each inequality to " slope - intercept " form, as such -

2x + 10y \leq 100,\\10y \leq 100 - 2x,\\y \leq - 1 / 5x + 10\\----------\\9x + y \leq 54,\\y \leq - 9x + 54

The graphed solutions would be in the attachment. I have colored the region with which the two intersect, and the fact that we are limited to quadrant 1. In this colored region there are 3 major points, ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ). We have to determine which of these are are maximum points, as the minimum are the same. Substitute these values ( ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ) ) into the equation f( x, y ) = 10x + 4y,

f ( x, y ) = 10( 5 ) + 4( 9 ),\\f ( x, y ) = 86 -\\f ( x, y ) = 10( 0 ) + 4( 10 ),\\f ( x, y ) = 40 -\\f ( x, y ) = 10( 6 ) + 4( 0 ),\\f ( x, y ) = 60

( 5, 9 ) resulted in the greatest amount, 86. That would make it our maximum point -

<u><em>Solution = Option A</em></u>

3 0
3 years ago
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