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madam [21]
3 years ago
15

A group of finance managers at a car dealership estimates thatt 23% of all cars purchased last year were leases.If a sample of 8

00 cars sold last year obtained, what is the that more than 208 cars are going to be leased? Draw and label the appropriate curve. Your work must include caculator commands
Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer:

p = 0.52392

Step-by-step explanation:

Here we have

p = 23% = 0.23

\hat p = 208/800 = 0.26

n = 800

q = 1-p = 0.77

α = 5% = 0.05

Here we have

Z test given by

z=\frac{\hat{p}-p}{\sqrt{\frac{pq}{n}}}

From which we have

From the Cpdf we have Probability = 0.0219, z = 2.016

Therefore from the z score = 0.0683, p = 0.52392 from z table.

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Evgesh-ka [11]
The answer of it is 10c

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3 years ago
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Solve for x. 13x - 7 = 136
aniked [119]
Add 7 on both sides to then left side cancels out and you end up with 13x=143 then you divide 13 on both sides and get x=11
3 0
3 years ago
A man watches 9/11 happen with $5.00 in his pocket. How many one dollar bills could he have when The Daily Telegraph began publi
Luda [366]

Answer:

$5.00

Step-by-step explanation:

It doesn't say his money has changed so it is still $5.00

4 0
3 years ago
A stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 50 cm/s. Find the rate at which th
Evgen [1.6K]

Answer:

1.) 15,708cm^2/s

2) 47,124cm^2/s

3.) 109,956cm^2/s

Step-by-step explanation:

Given the following:

50cm/s is the radius of the ripple per second , that is, radius(r) of ripple after t seconds = speed * time(t)

Speed = 50cm/s

r = 50t

.area of a circle(A) = πr^2

Rate of change of area with radius :

dA/dt = π2r . dr/dt

Speed of ripple created = 50cm/s; this is the rate at which the radius changes with time (dr/dt)

dr/dt = 50cm/s

Rate at which area is increasing with time:

dA/dt = π2r . dr/dt

dA/dt = π2(50t).50

dA/dt = 5000πt

After 1 second:

dA/dt = 5000π(1)

= 15,707.963cm^2/s

After 3 second:

dA/dt = 5000π(3)

= 47,123.889cm^2/s

After 7 second:

dA/dt = 5000π(7)

= 109,955.74cm^2/s

8 0
3 years ago
A sample of 71 eggs yields a sample mean weight of 2.00 ounces. Assuming that the population standard deviation = 0.590 ounces,
Sauron [17]

Answer:

0.070 is the standard error of the mean weight in estimating a confidence interval estimate        

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} =  2.00 ounces

Sample size, n = 71

Alpha, α = 0.05

Population standard deviation, σ = 0.590 ounces

Formula for standard error =

S.E=\dfrac{\sigma}{\sqrt{n}}

Putting values, we get,

S.E = \dfrac{0.590}{\sqrt{71}} = 0.07002\approx 0.070

Thus, 0.070 is the standard error of the mean weight in estimating a confidence interval estimate

5 0
3 years ago
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