Question

A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to the potential difference between the plates as they are being separated?

Answer 1

Answer:

The potential difference increases

Explanation:

from the relation $E= \frac{V}{d}$

where E= electric field (force per coulomb)

            V= voltage

            d= distance

Hence the voltage is going to be V= E×d.

Therefore this means that increasing the distance increases the voltage.