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const2013 [10]
3 years ago
15

One end point of a line segment is ( -3, -6 ) The length of the line segment is 7 units find four points that could serve as the

other end point of the given line segment
Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0

Answer:

<em>(-3, 1), (-3, -13), (4, -6), (-10, -6)</em>

Step-by-step explanation:

You can think of point (-3, -6) as the center of a circle of radius 7. Then all points on the circle are 7 units from point (-3, -6). There are 4 points 7 units away from point (-6, -3) whose coordinates are easy to find. Think of a vertical line and a horizontal line that go through point (-3, -6). Up and sown from point (-3, -6) are points (-3, 1) and (-3, -13). To the right and left of point (-3, -6) are points (4, -6) and (-10, -6).

Mrac [35]3 years ago
6 0

Hey lassie. Here si your answer for this question.

Answer: (4,-6), (-3,-13), (-10,-6), and (-3,1).

Hope this helps you.

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Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following
posledela

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{165.9}{6} = 27.65

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%

5 0
3 years ago
Please help 6TH GRADE MATH HELP ME OUT PLEASE
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▹ Answer

<em>d. 7/20</em>

▹ Step-by-Step Explanation

\frac{1}{4} + \frac{1}{10} \\= Common denominator is 20\\\\\frac{1}{4} = \frac{5}{20} \\\\\frac{1}{10} = \frac{2}{20}  \\\\\frac{5}{20} + \frac{2}{20} \\\\= \frac{7}{20}

Hope this helps!

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3 years ago
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Answer:

D. 16 inches by 8 inches

Step-by-step explanation:

We have been given an image of two rectangles and we are asked to find the dimensions of the enlarged rectangle.

Since we have been given that the original rectangle is enlarged b a scale factor of 4, so to find the dimensions of enlarged rectangle we will multiply the dimensions of original rectangle by 4.

\text{Length of enlarged rectangle}=4\times 4\text{ inch}

\text{Length of enlarged rectangle}=16\text{ inch}

\text{Width of enlarged rectangle}=4\times 2\text{ inch}

\text{Width of enlarged rectangle}=8\text{ inch}

Therefore, the dimensions of enlarged rectangle are 16 inches by 8 inches and option D is the correct choice.

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