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const2013 [10]
3 years ago
15

One end point of a line segment is ( -3, -6 ) The length of the line segment is 7 units find four points that could serve as the

other end point of the given line segment
Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0

Answer:

<em>(-3, 1), (-3, -13), (4, -6), (-10, -6)</em>

Step-by-step explanation:

You can think of point (-3, -6) as the center of a circle of radius 7. Then all points on the circle are 7 units from point (-3, -6). There are 4 points 7 units away from point (-6, -3) whose coordinates are easy to find. Think of a vertical line and a horizontal line that go through point (-3, -6). Up and sown from point (-3, -6) are points (-3, 1) and (-3, -13). To the right and left of point (-3, -6) are points (4, -6) and (-10, -6).

Mrac [35]3 years ago
6 0

Hey lassie. Here si your answer for this question.

Answer: (4,-6), (-3,-13), (-10,-6), and (-3,1).

Hope this helps you.

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Solve the system of equations.<br> <img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7By%3D220x-160%7D%20%5Catop%20%7By%3
Leni [432]

\begin{cases} y=220x-160\\ y=20x^2-400 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{\stackrel{\textit{\Large y}}{220x-160}~~ = ~~20x^2-400} \\\\\\ -160=20x^2-220x-400\implies 0=20x^2-220x-240 \\\\\\ 0=20(x^2-11x-12)\implies 0=x^2-11x-12 \\\\\\ 0=(x-12)(x+1)\implies x= \begin{cases} 12\\ -1 \end{cases}

\dotfill\\\\ x=12\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(12)-160}\implies y=2480 \\\\\\ x=-1\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(-1)-160}\implies y=-380 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (12~~,~~2480)\qquad (-1~~,~~-380)~\hfill

4 0
2 years ago
The second number in an ordered pie of numbers that corresponds to a point on a coordinate system is the
NNADVOKAT [17]

Answer:

The second number in an ordered pie of numbers that corresponds to a point on a coordinate system is the y<u>-value.</u>

3 0
3 years ago
paul , Nadia and Jim have some stickers. Nadia has 3 times as many stickers as jim. Paul has 25 stickers more that Nadia. Paul a
alexandr402 [8]
Nadia = 3x than Jim
Paul = 25+ than Nadia
Jim = ?
Nadia and Paul = 85

85-25 = 60
(Subtract Nadia's and Paul's stickers all together with the stickers that Paul have more so both of the stickers are balance)

Nadia = 60/2 =30
Paul = 30+25 =55

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#Jim have 10 stickers


4 0
3 years ago
Any help with these two ratio problems are highly appreciated.
Lesechka [4]
A. 3 tbsp per 2 tsp
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4 0
3 years ago
The equation of a parabola is y=x^2-10x+27. Write the equation in vertex form
azamat

Answer:

\large \boxed{y = (x - 5)^{2} + 2 }

Step-by-step explanation:

y = x² - 10x + 27

y = ax² + bx + c

This is the general form of the equation for a parabola.

We must convert it to the vertex form

y = (x - h)² + k, where (h,k) are the coordinates of the vertex.

We can do this by completing the square.

\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}The figure below shows that your parabola has its vertex at (5,2).

4 0
3 years ago
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