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3 years ago

How do you graph a possible situation?

1 answer:

4 0

To graph a situation that would involve a linear graph, first determine your x and y axes.
The x-axis will be the independent variable, one that does not change based on other variables. An example is time.

The y-axis, the dependent variable, depends on the independent variable.

The model equation for a linear line is y = mx + b.
"m" is the slope, and the "b" is the y-intercept (where the graph crosses the x-axis at x=0).

For example, a situtation could be that Joe starts with $10 in his account and adds $5 every day to his account.
The x-axis is time in days.
The y-axis is amount of money in his account.
The slope, or rate of change is 5.
The y-intercept, the amount of money he has at x=0 (0 days) is $10.

The equation would be y = 5x + 10
To draw this, plot the y-intercept at (0, 10), and the next point would be 5 units up and one unit to the right because the slope is 5, or 5/1 (remember slope is rise over run: "rise" up 5 and "over" to the right 1).

You might be interested in

Which line has an undefined slope? A y = 0 B y = 2 C x = y D x = 2

PolarNik [594]

Learn this :
VUX -- vertical line, undefined slope, represented by x = a number.
HOY -- horizontal line, 0 slope, represented by y = a number

so the line with the undefined slope is going to be x = 2

5 0

2 years ago

Read 2 more answers

(27x4 - 18x3 + 9x 2) = 3x Answer ASAP

shepuryov [24]

Answer:

x = 24

Step-by-step explanation:

27 x 4 = 108

18 x 3 = 54

9 x 2 = 18

108 - 54 + 18 = 3x

72 = 3x

72/3 = x

24 = x

7 0

3 years ago

Please let me know if this is correct and if not what is the correct answer. Thanks

vlada-n [284]

There’s nothing on the picture

6 0

2 years ago

Read 2 more answers

Enter the equation of the circle described below. Center (3, -2), radius = 5

Alik [6]

Answer:

$(x-3)^{2} +(y+2)^{2} =5^{2}$

Step-by-step explanation:

The equation of the circle with center A=(a,b) and radius = r are:

$(x-a)^{2}+(y-b)^{2} =r^{2}$

When A=(3,-2) and radius=r=-5

$(x-3)^{2} +(y+2)^{2} =5^{2}$

5 0

3 years ago

CAN SOMEONE PLEASE WRITE A EQUATION OF THIS LINE!!

serious [3.7K]

Answer (assuming it can be in slope-intercept form):

y = -x - 1

Step-by-step explanation:

When knowing the slope of a line and its y-intercept, you can write an equation to represent it in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.

1) First, find the slope of the equation, or m. Pick any two points from the line and substitute their x and y values into the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . I chose the points (0, -1) and (-1, 0):

$m = \frac{(0)-(-1)}{(-1)-(0)} \\m = \frac{0+1}{-1-0} \\m = \frac{1}{-1} \\m = -1$

Thus, the slope is -1.

2) Now, find the y-intercept, or b. The y-intercept of a line is the point at which the line crosses the y-axis. By reading the graph, we can see that the line intersects the y-axis at the point (0,-1), therefore that must be the y-intercept.

3) Now, substitute the found values into the y = mx + b formula. Substitute -1 for m and -1 for b:

$y = -x -1$

5 0

3 years ago

Read 2 more answers