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Svetradugi [14.3K]

3 years ago

5

I NEED HELP ASAP Find the area of this parallelogram.

2 answers:

Flura [38]3 years ago

8 0

Answer:

B

Step-by-step explanation:

The area (A) of a parallelogram is calculated as

A = bh ( b is the base and h the perpendicular height )

Here b = 15 and h = 5, thus

A = 15 × 5 = 75 cm² → B

ANEK [815]3 years ago

3 0

Answer:

75cm2

Step-by-step explanation:

area of paralelogram is H*L

and both H and L are given H=5 L=15

15*5=75

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bonufazy [111]

Answer:

30.35

Step-by-step explanation:

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3 years ago

Are these triangles congruent ?

Vadim26 [7]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Trapezoids and kites

lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 36\degree +70\degree+m$ .

$\Rightarrow 106\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles of the kite are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

$|RH|^2=12^2+20^2$

$|RH|^2=144+400$

$|RH|^2=544$

$|RH|=\sqrt{544}$

$|RH|=4\sqrt{34}$

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore $m$

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

$m$

$\Rightarrow m$

$\Rightarrow m$

QUESTION 7

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 48\degree +110\degree+m$ .

$\Rightarrow 158\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

$|BC|^2=4^2+7^2$

$\Rightarrow |BC|^2=16+49$

$\Rightarrow |BC|^2=65$

$\Rightarrow |BC|=\sqrt{65}$

QUESTION 9.

The sum of the interior angles of a trapezium is $360\degree$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the measure of angle M and K are congruent.

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

6 0

3 years ago

I need help with geometry

VLD [36.1K]

Answer:

180-71

=109

the last one

5 0

3 years ago

A truck weighing 150kN and travelling at 2m/sec impacts with a buffer

FrozenT [24]

The maximum compression of the spring is 0.276 m

Step-by-step explanation:

First of all, we calculate the spring constant of the spring, by using Hooke's law:

$F=kx$

where

F = 10 kN = 10,000 N is the force applied

x = 1.25 cm = 0.0125 m is the corresponding compression of the spring

k is the spring constant

Solving for k,

$k=\frac{F}{x}=\frac{10,000}{0.0125}=8\cdot 10^5 N/m$

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write

$\frac{1}{2}mv^2=\frac{1}{2}kx^2$ (1)

where

m is the mass of the truck

v = 2 m/s is the initial speed of the truck

$k=8\cdot 10^5 N/m$ is the spring constant

x is the compression of the spring

The mass of the truck can be found from its weight:

$m=\frac{W}{g}=\frac{150,000 N}{9.81 N/kg}=15,290 kg$

So now we can re-arrange eq.(1) to find the compression, x:

$x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(15,290)(2)^2}{8\cdot 10^5}}=0.276 m$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

6 0

3 years ago