All categories

2 years ago

Help help help help help

Mathematics

1 answer:

Blizzard [7]2 years ago

7 0

Answer:

x = 12

Step-by-step explanation:

Becuase 6/12 = 2 and 9 + 2 = 11

You might be interested in

Find the distance between -3 and 4. A) -12 eliminate b) -7 c) -1 d) 7

n200080 [17]

The formula of a distance between A and B = |B - A|.

We have -3 and 4. Substitute:

|4 - (-3)| = |4 + 3| = |7| = 7

<h3>Answer: d) 7</h3>

8 0

3 years ago

The yearbook club had a meeting. The club has 30 people and three fifths of the club showed up for the meeting how many went to

cestrela7 [59]

Answer:

there are 45 people in the group

2/3xA=30

2A=30x3

A=90/2

A=45

8 0

3 years ago

Read 2 more answers

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

Let $\bar X$ = sample mean heights

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)

= 0.99492 or 99.5%

The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.

Therefore, 99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

3 0

3 years ago

If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.

nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)} ^2 = {det (adjacent of A)} ^2

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2 = {det(A) ^3−1 }^2

=(11)^2×2 = 11^4

=146.41

5 0

3 years ago

The Buffalo Bills football team wanted to buy new footballs. what did the team have to pay per football? Be sure to explain all

iogann1982 [59]

Answer: I don't see the amount per football

Step-by-step explanation:

6 0

3 years ago