All categories

3 years ago

2 3 + 6^{2} ÷ 9 i need help with this one

Mathematics

1 answer:

creativ13 [48]3 years ago

5 0

Answer: 7

Step-by-step explanation:

3+6^(2) / 9

3 + 36 / 9

3 + 4

You might be interested in

The cost for a company to produce a part for d days is represented by the function f(d)=325d + 8,795. What does the value 8,795

Anna007 [38]

Answer:

Step-by-step explanation:

A, B are wrong since 8,795 is a constant, it doesn’t change;

D is wrong since it is the starting cost, not total cost

4 0

3 years ago

a baker is making bread dough.He uses 3 cups of flour for every 8 ounces of water. How many cups of flour will be use if he used

Nataliya [291]

Answer:

36 cups of flour

Step-by-step explanation:

if 3 cups of flour=8 ounces.what about 96 onces you cross multiply

7 0

3 years ago

a rectangular playground is 40 meters by 10 meters. its area will be covered with shredded tires. each bag of shredded tires cov

Lena [83]

First, we need to find the area of the rectangular playground.
To do this, we must multiply 40 by 10.
We get 400 meters².
Now divide 400 by 200 and you get 2.
That means 2 bags will be needed to cover the entire area of the playground.
To find the price, multiply 30 by 2.
The total cost for this project will be $60.
Hope this helped you out! :)

6 0

3 years ago

Can someone please help??

Vsevolod [243]

Answer:

let the number of cows = x

let the number of chickens = y

since there are 42 heads:

x + y = 42

and since a cow has 4 legs, and a chicken has 2

4x + 2y = 144

from first equation:

x + y = 42

x = 42 - y (now, we will substitute this in the second equation)

4(42 - y) + 2y = 144

168 - 4y + 2y = 144

2y = 168 - 144

2y = 24

y = 12

now, we know the number of chickens. we will replace y with 12 in the first equation since it is more simpler

x + 12 = 42

x = 30

So, there are 30 cows and 12 chickens

Brainly it if you find the answer helpful

5 0

3 years ago

Could you please look at this question?

MrMuchimi

Answer:

a. see attached

b. H(t) = 12 -10cos(πt/10)

c. H(16) ≈ 8.91 m

Step-by-step explanation:

The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.

The function describing the height will be ...

H(t) = 12 -10cos(πt/10)

The graph of it is attached.

See part a.

The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.

H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983

The height of the rider 6 seconds after passing the top will be about 8.91 m.

8 0

3 years ago