Write y=2x^2+12x+1 in vertex form.

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

8 0

Answer:

y = 2(x + 3)^2 - 17.

Step-by-step explanation:

y=2x^2+12x+1

y = 2(x^2 + 6x) + 1

y = 2[( x + 3)^2 - 9] + 1

y = 2(x + 3)^2 - 18 + 1

y = 2(x + 3)^2 - 17.

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Can someone please help me with this

Nesterboy [21]

Answer:

m∠Q = 121°

m∠R = 58°

m∠S = 123°

m∠T = 58°

Step-by-step explanation:

The sum of the interior angles of a quadrilateral = 360°

Create an expression for the sum of all the angles and equate it to 360, then solve for x:

∠Q + ∠T + ∠S + ∠R = 360

⇒ 2x + 5 + x + 2x + 7 + x = 360

⇒ 6x + 12 = 360

⇒ 6x = 360 - 12 = 348

⇒ x = 348 ÷ 6 = 58

So now we know that x = 58, we can calculate all the angles:

m∠Q = 2x + 5 = (2 x 58) + 5 = 121°

m∠R = x = 58°

m∠S = 2x + 7 = (2 x 58) + 7 = 123°

m∠T = x = 58°

5 0

1 year ago

The sides of a right triangle measure 6 times the square root of 3, 6 inches, and 12 inches. If an altitude is drawn from the ri

VARVARA [1.3K]

Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.

Step-by-step explanation:

Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.

Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.

Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB

⇒ 6/x = 12/6

⇒ 6/x = 2

⇒ x = 3 inches

Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.

⇒ $AD^{2} + BD^{2} = AB^{2}$