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earnstyle [38]
3 years ago
8

The energy used by an appliance which operates at 240 volts at 15 amp for 4 hr. is A. 0.92 kwhr. B. 3.45 kwhr. C. 14.4 kwhr. D.

60.0 kwhr
Computers and Technology
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

C. 14.4 kwhr.

Explanation:

To calculate the energy used by appliance first calculate the power. The formulae for calculating power(<em>P</em>) is P= I \times V, where V stands for voltage and I stands for current.

In the given problem,  V = 240 volts and I = 15 amp. Therefore,

P=240 \times 15 =3600\ watt(w) = 3.6\ kw

Now, formulae for calculating energy used i.e. work(W) is W = P\times t, where <em>t</em> is the time.

In the given question time is 4 hr. Therefore energy used will be,

Energy used (W) = 3.6\times4 =14.4\ kwhr.

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Whereas &lt; is called a relational operator, x &lt; y is called a(n) ________. A) Arithmetic operator B) Relative operator C) R
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RideAnS [48]

Answer:

// code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int length=10,height=7,width=5;

   // find the volume of

   int vol=length*height*width;

   // find the surface area

   int sa=2*(length*width+length*height+height*width);

   // find the perimeter

   int peri=4*(length+width+height);

   // print the volume

   cout<<"Volume is: "<<vol<<" cm^3."<<endl;

   // print the surface area

   cout<<"Surface area is: "<<sa<<" cm^2."<<endl;

   // print the perimeter

   cout<<"Perimeter is: "<<peri<<" cm."<<endl;

return 0;

}

Explanation:

Declare and initialize length=10, width=5 and height=7.calculate volume by multiply length, width and height and assign to variable "vol".Then find the surface area as 2*(length*width+length*height+height*width) and assign it to variable "sa".Then find the perimeter as 4*(length+width+height) and assign to variable "peri". Print the volume, perimeter and surface area.

Output:

Volume is: 350 cm^3.

Surface area is: 310 cm^2.

Perimeter is: 88 cm.

8 0
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