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Likurg_2 [28]
3 years ago
6

suppose you invest 400 at an annual interest rate of 7.6% compounded continuously. How much will you have in the account after 1

.5 years? Round the solution to the nearest dollar.
Mathematics
2 answers:
dlinn [17]3 years ago
3 0
A=pe^rt
A=400×e^(0.076×1.5)
A=448.30
sertanlavr [38]3 years ago
3 0

Answer:

$ 448

Step-by-step explanation:

Here, the principal amount, P = $ 400

Rate of interest, r = 7.6 % = 0.076

Time, t = 1.5 years,

Thus, the amount that is compounded continuously for 1.5 years is,

A= Pe^{rt}

=400 e^{0.076\times 1.5}

=400e^{11.4}=400\times1.12075212488=448.300849954\approx 448

Hence, we will have $ 448 after 1.5 years.

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3 years ago
An actor invests some money at 7%, and $48000 and more than twotimes the amount of 9%. The total annual interest earned from the
forsale [732]

Answer:

At 7% $54,000

At 9% $156,000

Step-by-step explanation:

Let x be the amount invested at 7%, Then 2x + 48000 will be the amount invested at 9%

We know that:

7% = 0.07 & 9% = 0.09

So we can write the interest equation as follows:

0.07x + 0.09 (2x + 48000) = 17820

0.07x + 0.18x + 4320 = 17820

0.25x + 4320 = 17820

Subtracting 4320 from both sides of the equation we get:

0.25x = 17820 - 4320

0.25x = 13500

Dividing both sides of the equation by 0.25 we get:

x = 13500 / 0.25

x = $54,000 invested at 7%

&

2 x 54000 + 48000

= $156,000 invested at 9%

Hence the amount invested at 7% is $54,000.

& the amount invested at 9% is $156,000.

5 0
3 years ago
The cost to produce a product is modeled by the function f(x) = 5x^2 − 70x + 258, where x is the number of products produced. Co
Advocard [28]

The minimum of a quadratic function, with a positive coefficient a, is its vertex.

Let's find the x₀ coordinate.

f(x) = 5x^2 -70x + 258\\\\x_0=\dfrac{-b}{2a}=\frac{-(-70)}{2*5}  =\frac{70}{10} =7

Now we need to find y₀ coordinate. That will be the minimum of function.

y_0=5\times7^2-70\times7+258=13

So, the minimum cost to produce the product is $13

Decompose 5x^2 − 70x + 258 into multipliers

5x^2 - 70x + 258=(5x^2-70x+245)+13=5(x^2-14+49)+13=\\=5(x-7)^2+13

Answer: 5(x − 7)^2 + 13; The minimum cost to produce the product is $13.

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