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2 years ago

6

Ahhh if someone can,please answer asap! 20 points!

1 answer:

matrenka [14]2 years ago

6 0

Answer:

x = 32

The 9 and 4 ball are farthest from each other.

Step-by-step explanation:

Since the angles of a triangle add up to 180 degrees, you can create the equation (x-5)+(2x+1)+(3x-8)=180, which can be simplified to 6x-12=180. That means the value of x is 32. That means the 9 ball is at 27 degrees, the 4 ball is at 65 degrees, and the 5 ball is at 88 degrees. Based on the angles, the farthest distance would be between balls 9 and 4.

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I need trigometry help

Alex Ar [27]

A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.

4 0

3 years ago

Find sin theta if cot theta = -2 and cos theta < 0

Katarina [22]

cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)

So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.

Recall that

cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)

so that

sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)

sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)

Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :

sin(<em>θ</em>) = 1 / √((-2)² + 1)

sin(<em>θ</em>) = 1/√(5)

6 0

2 years ago

For which of the following is x=-5 a solution. Select all that apply

mafiozo [28]

I think the answer is 3 but I’m not sure.

Hope this helps!

6 0

3 years ago

According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h

andreyandreev [35.5K]

Answer:

The graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph $f(x)=x^2-4x+3$

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation $f(x)=x^2-4x+3$ the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, $f(x)=x^2-4x+3=0$

This is a quadratic equation, $x^2-4x+3=0$

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

$x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0$

$\Rightarrow x(x-1)-3(x-1)=0$

$\Rightarrow (x-3)(x-1)=0$

Using zero product property, $a\cdot b=0 \Rightarrow a=0\ or \ b=0$

$\Rightarrow (x-3)=0$ or $\Rightarrow (x-1)=0$

$\Rightarrow x=3$ or $\Rightarrow x=1$

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

3 0

3 years ago

pantera1 [17]

Answer:

Step-by-step explanation:

-22

8 0

3 years ago