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3 years ago

Simplify by performing long division.

Mathematics

1 answer:

olga_2 [115]3 years ago

3 0

Answer:

the answer is A. 3x-2+2/x+1

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The point B(-6, -6) is translated 4 units right. What are the coordinates of the resulting point, B′?

Lady bird [3.3K]

Answer:

-2

Step-by-step explanation:

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3 years ago

Andrea constructed a triangle. Angle 1 and 3 are the same size and angle 2 has a measurement of 70 degrees. What is the measurem

Verdich [7]

Answer:

Step-by-step explanation:

By triangle sum theorem,

Sum of all angles of a triangle is 180°.

m∠1 + m∠2 + m∠3 = 180°

(m∠1 + m∠3) + m∠2 = 180°

2(m∠1) + 70° = 180° {Given → m∠1 = m∠3]

2(m∠1) = 110°

m∠1 = 55°

Therefore, m∠1 = m∠3 = 55°

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3 years ago

THE TEACHER WONT HELP ☺️ pls

Readme [11.4K]

answer:

2/5=0.4

2/5=40%

step-by-step explanation:

to get 2/5 as a decimal you can simply just divide 2÷5 which is 0.4

and from there you can use 0.4 to find the percentage multiply 0.4 x 100 which is 40

good luck :)

hopefully, this helps

have a great day !!

4 0

3 years ago

How many 0.6 liter glasses can help you fill up with a 4.5 liter pitcher?<br><br> need work also

Kisachek [45]

You can fill up 7.5 liter glasses with a 4.5 liter pitcher. This is because 4.5 <span>÷ .6 = 7.5. Just use long division! :)</span>

6 0

3 years ago

Read 2 more answers

Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr

Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
$

Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0

3 years ago