By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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Answer:
2x²√13
Step-by-step explanation:
√52x⁴ = √4×13×x⁴ = 2x²√13
The answer to this question is actually just simple arithmetic. At the end of the first round, Katie and Jenny will have 100 points each. In the second round, Katie and Jenny will have 200 points and 300 points respectively. At the third round, Katie and Jenny will both have 400 points. At the fourth round, Katie and Jenny will have 800 and 600 points respectively. So the turn at which Katie will have more points than Jenny is the fourth round since Katie has 800 and Jenny has 600.
Answer:
I think that is a function
Step-by-step explanation:
