Sin (tan^(-1)X)
Sin (1/tan X)
Sin (1/1 / tan X/1)
Tan X = sin X/cos X
Sin (1/1 / sin X/cos X)
Sin (1/1 • cos X/Sin X)
Sin (cos X/sin X )
Cos X.
I believe the correct answer is cos X.
Answer:
m∠KHL = 43°
Step-by-step explanation:
From the picture attached,
m∠KHL ≅ m∠GHL [Given in the picture]
Now substituting the values of the angles,
(3x + 1) = (5x - 27)
1 + 27 = 5x - 3x
28 = 2x
14 = x
m∠KHL = (3x + 1)° = (3 × 14) + 1
= 42 + 1
= 43°
Therefore, measure of ∠KHL = 43°
Answer:
option 1 is equivalent to 3^2.3^5
Answer:
e = -1/2
Step-by-step explanation:
4/3 = -6e - 5/3
transfer -6e to the right
4/3 = -5/3 -6e
Find the LCM of 3,3and 1
and their LCM is 3. So, divide all through by 3
3(4/3) = 3(-5/3) - 6e × 3
4 = -5 -18e
combine
4 + 5 = -18e
9 = -18e
divide by -18
9/ -18 = -18e/ -18
-1/2 = e
e = -1/2
$32/8=Answer
Answer=$4
She can spend $4 on each person.
Hope this helps!