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Solnce55 [7]
3 years ago
12

I need the expression it the answer. Please help me. 10 points.

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0
On number 1, it is 5-2, not 2-5.
On number 2, 3(4+12).
On number 3, (15/3)+10
On number 4, 2+6*4
On number 5, it is correct
On number 6, 2(8-2)
On number 7, it is correct
On number 8, (8*1/4)+11
Hope this helps
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Division of whole numbers is associative, true or false? If false then what is correct? Plz and Thank you for the help!!
Sav [38]

Answer:

Division is not associative.

The associative property applies only to addition and multiplication, not subtraction or division.

4 0
3 years ago
Please help.
Scorpion4ik [409]

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About 30°F.

Step-by-step explanation:

-17 is close to -20 so -20+20=0 then it says greater then 10 so then 0+10.

I dont know if my logic makes sense, please tell me if I'm right

6 0
3 years ago
Barkly Doghouses charge 50$per square meter for their doghouses. Complete the table to show this is a porptional relationship
Solnce55 [7]
50 to 1
100 to 2
150 to 3
200 to 4
It's proportional
3 0
4 years ago
LESSON
bagirrra123 [75]
C is the answer hope that helps have a good day
5 0
3 years ago
Calculate the integral s f · ds, where s is the entire surface of the solid half ball x2 + y2 + z2 ≤ 1, z ≥ 0, and f = (x + 3y5)
SSSSS [86.1K]
The divergence theorem applies since \mathcal S is a closed surface. We have

\displaystyle\iint_{\mathcal S}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal V}\nabla\times\mathbf f(x,y,z)\,\mathrm dV

where \mathcal V is the space enclosed by the surface \mathcal S. The divergence of the given vector field is

\nabla\times\mathbf f(x,y,z)=\dfrac{\partial(x+3y^5)}{\partial x}+\dfrac{\partial(y+10xz)}{\partial y}+\dfrac{\partial(z-xy)}{\partial z}=1+1+1=3

So we can write the volume integral (in spherical coordinates) as

\displaystyle3\iiint_{\mathcal V}\,\mathrm dV=3\int_{\varphi=0}^{\varphi=\pi/2}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=1}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{4\pi}3
6 0
3 years ago
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