What is another way to write 5 + 5 + 5 using a different operation?

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

6 0

Answer:

5x3 (5 times 3)

Step-by-step explanation:

there are 3 five adding up, so the 5 is being multiplied 3 times.

Therefore, its 5 times 3

tresset_1 [31]3 years ago

5 0

Answer:

5 × 3=15 and 5+5+5=15 that's all

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Factor completely 3x - 12. (1 point)

yarga [219]

Answer:

3(x - 4)

Step-by-step explanation:

Given

3x - 12 ← factor out 3 from each term

= 3(x - 4)

3 0

3 years ago

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$