1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cricket20 [7]
3 years ago
5

Find the sum of 7/13 and 11/26.

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
5 0

Answer:

25/26


Step-by-step explanation:

7/13 + 11/26

The common denominator is 26

7/13 *2/2 +11/26

14/26 + 11/26

25/26

timofeeve [1]3 years ago
4 0

Answer:

The sum of 7/13 and 11/26 is 25/26.

Step-by-step explanation:

First off you find the LCM (Least Common Multiple) between the denominators which are 13 and 26 in this case. The LCM between 13 and 26 would be 26. You then change 13 to the denominator of 26. 13x2 is 26 so whatever you do to one side or one part, you have to do to the other. Now, you will multiply 7x2 to get 14. Your final fractions are 14/26 and 11/26. When you add 14/26 and 11/26, you get 25/26. Hope this helps! :)


<h2>CloutAnswers</h2>
You might be interested in
Choose the correct sum of the polynomials (4x3 − 2x − 9) (2x3 5x 3). 6x3 − 3x − 6 2x3 − 7x − 12 6x3 3x − 6 2x3 3x − 3.
dimaraw [331]

The correct sum of the polynomial is \rm 6x^3 + 3x - 6.

We have to determine

The correct sum of the polynomials.

<h3>Sum of the polynomials</h3>

Sum of the polynomials is just a matter of combining like terms, with some order of operations.

Then,

The correct sum of the polynomial is;

\rm (4x^3 - 2x - 9) + (2x^3 + 5x + 3) \\\\ 4x^3 - 2x - 9 + 2x^3 + 5x + 3\\\\ 6x^3 + 3x - 6

Hence, the correct sum of the polynomial is \rm 6x^3 + 3x - 6.

To know more about the sum of the polynomial click the link is given below.

brainly.com/question/9465649

5 0
2 years ago
If p and q prime number greater than 2which of the following is not even integer ? a.p+q b.p×q c.p^2-q^2 d.p-q​
egoroff_w [7]

B, because every prime number greater than 2 is odd, and the product of two odd numbers is odd.

7 0
3 years ago
Read 2 more answers
Is this the right answer?
Ne4ueva [31]
Yes your answer is solved correctly
6 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Can anyone please explain? Need some help :)
DedPeter [7]

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = \dfrac{\sqrt{3} }{4}s^2

Side Length, s=6 Units

\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units

Area of the Hexagon

= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)

7 0
3 years ago
Other questions:
  • As Mars revolves around the sun, it travels at a speed of approximately
    9·1 answer
  • McKenna pays $16 per month for a gym membership. In addition, she pays $2 per Pilates class.
    10·1 answer
  • Is 5/7 a rational number? explain
    12·2 answers
  • By the Triangle Inequality Theorem which set of side lengths could create a triangle? A) 5, 10, 4 B) 5, 7, 13 C) 7, 9, 3 D) 10,
    6·2 answers
  • A store bought 300 toys at a cost of ​$24 each. The store sold all the toys at a percent markup of 25 %. Find the total selling
    6·1 answer
  • Need help for one question for geometry !
    14·1 answer
  • If f(x) = x2 – 3x and<br> g(x) = 4x + 2, which of the following is equal<br> to f(g(3))?
    10·1 answer
  • Change 4/50 into percent.
    6·1 answer
  • Help pls I don’t get it
    9·1 answer
  • Find the surface area
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!