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3 years ago

5

Help ? I need steps on how to do this

1 answer:

Furkat [3]3 years ago

8 0

<em>Answer</em><em> </em><em>:</em><em>-</em><em> </em>

<em>the</em><em> </em><em>quoti</em><em>ent</em><em> </em><em>is</em><em> </em><em>(</em><em> </em><em>4</em><em>x</em><em>²</em><em> </em><em>-</em><em> </em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

Step-by-step explanation:

[ Refer to the attachment for steps ]

We have to eliminate the highest degree coefficient in each step.

And as in division of normal numbers we subtract the things here we do the same ,

but while subtracting we have to take care about the signs !

The negative sign changes the negative sign into positive sign and positive sign into negative sign.

Whereas , a positive sign don't changes the sign.

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Step-by-step explanation:

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4 years ago

Which of the following equations is equivalent to x - y = 5?

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3 years ago

Read 2 more answers

Consider the quadratic function f(x)=−x^2+x+30

yaroslaw [1]

Answer:

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The yy-intercept is $y = 30$ .

Step-by-step explanation:

Given a quadratic function in the following format:

$f(x) = ax^{2} + bx + c = 0, a \neq 0$

The x-values of the x-intercepts are $x_{1}, x_{2}$ , given by the following formulas.

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

We have that:

$f(x) = -x^{2} + x + 30$

This is not in the format above. I will multiply by (-1), so we have:

$f(x) = x^{2} - x - 30$

So, $a = 1, b = -1, c = -30$

$\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121$

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6$

$x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5$

This means that

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The y-intercept is the value of f(x) when x = 0. So

$f(x)=−x^{2}+x+30$

$f(0) = 30$

The yy-intercept is $y = 30$ .

5 0

3 years ago