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jeka57 [31]
3 years ago
13

The lengths of a lawn mower part are approximately normally distributed with a given mean mc021-1.jpg = 4 in. and standard devia

tion mc021-2.jpg = 0.2 in. What percentage of the parts will have lengths between 3.8 in. and 4.2 in.?
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
5 0
<span>The best answer that is given to the question that is being presented above would be 68%. Since it is normally distributed and the lengths' range fall between the first lower and upper standard deviations of the distribution (which is 68%), then the answer is 68%. </span>
Lostsunrise [7]3 years ago
5 0

Answer: 68

Step-by-step explanation:

You might be interested in
An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
Andrej [43]

Answer:

Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

Probability of N Divisible by 15 - 0.066

Probability of N Divisible by 105 - 0.0095

Step-by-step explanation:

Given data:

Integer N {1,2,.....10^3}

Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

Probability of N divisible by 3 {N%3 = 0 } = \frac{333.3}{1000} = 0.33

total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

Probability of N divisible by 5 {N%5 = 0 } = \frac{200}{1000} = 0.2

total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

Probability of N divisible by 7 {N%7 = 0 } = \frac{142.857}{1000} = 0.413

total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

3 0
3 years ago
Read 2 more answers
ANSWER ANSWER ANSWER I ONLY GOT TIL TOMORROW AND I WILL MARK U THE BRAINLYESS
love history [14]

Boi stop cheatin and draw ur own tape diagram

6 0
3 years ago
Please help ASAP it’s due today
Westkost [7]

Answer:

1) At least 6.

2) $2194.8

3) $2326.49

4) 38 mph on average.

Step-by-step explanation:

Comment if you do need the steps

7 0
2 years ago
Someone please help im stuck
BARSIC [14]
The answer is b, -11.
plug in 3 as the input and solve.
4 0
3 years ago
Lena is 10 years old. She asks her dad how old he is. He tells her that the lowest common multiple of their ages is 14 times the
Ksju [112]

Answer:

  35

Step-by-step explanation:

We know the factors of Lena's age are 2 and 5. The least common multiple must have these factors and the factors of 14, so will at least have factors of 2, 5, and 7.

Apparently, the dad's age is 5·7 = 35.

___

The GCF is 5; the LCM is 70 = 5×14.

_____

Sometimes, I use a little 3-part diagram to think about LCM and GCF. Here, it would look like ...

  (2 [5) 7]

where the numbers in curved brackets (2·5) and the numbers in square brackets [5·7] are factors of the two numbers of concern (Lena's age, her dad's age). The middle number in both brackets [5) is the greatest common factor, and the product of all three numbers is their least common multiple.

Here, the product of outside numbers, 2·7 = 14, represents the ratio of the LCM to the GCF. We know that Lena's age has factors of only 2 and 5, so the numbers in the diagram have to be (2[5)7], where 2 and 7 are on the ends and 5 is in the middle.

7 0
3 years ago
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