All four angles are exterior angles of the quadrilateral.
We know that the sum of exterior angles of any polygon is 360 ° .
So we can add together the four angles and solve for x:
(x+16)+(3x-1)+6x+5x = 360
15x+15=360
15x=345
x=345/15=23 °
Answer:
Area of Trapezoid is 39 unit²
Step-by-step explanation:
Given as :
For A Trapezoid
The measure of base side 1 =
= 10 unit
The measure of base side 2 =
= 16 unit
The height of the Trapezoid = h = 3 unit
Let The Area of Trapezoid = A square unit
<u>Now, From Formula</u>
Area of Trapezoid =
× (sum of opposite base) × height
I.e A =
× (
+
) × h
Or, A =
× (10 unit + 16 unit) × 3 unit
Or, A =
× (26 unit) × 3 unit
Or, A =
× 78 unit²
Or, A =
unit²
I.e A = 39 unit²
So, The Area of Trapezoid = A = 39 unit²
Hence, The Area of Trapezoid is 39 unit² . Answer
She has to donate 46 more 127 x 2 +n=300 You have to add 127 twice, which gives you 254. Then you subtract that from 300.