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2 years ago

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The school auditorium can hold at most 480 people. There were 185 advance tickets sold for the school play. Write and solve an i

nequality to represent the number of people who can attend the play if all the people who bought advance tickets attend the play.

1 answer:

attashe74 [19]2 years ago

3 0

Answer:

p + 185 ≤ 480

p ≤ 295

At most 295 people can attend the play

Step-by-step explanation:

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1.012 - 0.809 +2.75<br><br>give me the answer

meriva

Answer:

2.953

Step-by-step explanation:

Following the order of operations, work from left to right for addition/subtraction.

Subtraction:

$\begin{array}{r r r r r} ^0\diagup\!\!\!\!1 &. & ^10 & ^0\diagup\!\!\!\!1&^1 2\\ -\quad0&.&8&0&9\\\cline{1-5}0&.&2&0&3\\\cline{1-5} \end{aligned}$

Addition:

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Therefore, the solution is 2.953

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2 years ago

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PLZ HURRY IT'S URGENT!!!

mr Goodwill [35]

Answer:

25 two point shots

25 three point shots

2x+3y<100 is that the one missing the sign?

Step-by-step explanation:

25*2=50

25*3= 75

50+75= 125

2x+3y has to be over 100 points

so 2x+3y<100

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3 years ago

The volume of a box is 400in3. if the height is 10in and the length is 8in, what is the width of the box (volume=l•w•h)

tankabanditka [31]

10•8=80
so something times 80 will equal 400
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3 years ago

So sorry to ask another question but I need some help-

Vika [28.1K]

Answer:

14x + 23

Step-by-step explanation:

The lengths of three sides of a triangle are 5x + 9 feet, 2x + 14 feet, and 7x feet.

The perimeter of a triangle: the sum of all of its sides.

5x + 9 + 2x + 14 + 7x

14x + 23

It's the expression of the perimeter of the triangle. Once you will be asked to find x, you'll probably be given the exact perimeter of the triangle.

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2 years ago

Sulfur compounds cause "off-odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compoun

aev [14]

Answer:

a) $29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

b) $z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

$p_v =P(z>1.988)=0.0234$

If we compare the p value and the significance level given $\alpha=Step-by-step explanation:Previous conceptsA confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". 
The margin of error is the range of values below and above the sample statistic in a confidence interval. 
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". 
Part a
Data given: 30 30 42 35 22 33 31 29 19 23
We can calculate the sample mean with the following formula:[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}= 29.4$ the sample mean

$\mu$ population mean (variable of interest)

$\sigma=7$ represent the population standard deviation

n=10 represent the sample size

95% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

Part b

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 25$

Alternative hypothesis : $\mu>25$

Compute the test statistic

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

Give the appropriate conclusion for the test

Since is a one side right tailed test the p value would be:

$p_v =P(z>1.988)=0.0234$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

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3 years ago