Answer:
Specific Learning Outcomes:
Solve problems that involve finding powers of a number
Description of mathematics:
In this problem students work with powers of numbers and, as a consequence, come to understand what is happening to the numbers.
Students also see how an apparently enormous and difficult calculation can be broken down into manageable parts. The students should come to realise that there are only a limited number of unit digits obtained when 7 is raised to a power. Further, these specific digits 'cycle round' as the power of 7 increases. This cycle is 7, 9, 3, 1, 7, 9, …
The same is true of the digit in the tens place.
Answer: 28/45
Step-by-step explanation:
Not really sure what you are looking for, but this is how to solve equations such as these.
Let:
x = number of pounds of granola
y = numer of pounds of walnuts
The equation he can use to compute the total cost would be:
$2.00x + $6.00y = $12.00
We know that he bought 3 pounds of granola, so we plug in that for the x value:
$2.00(3) + $6.00y = $12.00
$6.00 + $6.00y = $12.00
To isolate the unknown value which is y, we first need to subtract $6.00 from both sides of the equation:
$6.00 + $6.00y - $6.00 = $12.00 - $6.00
$6.00y = $6.00
Then we divide both sides by $6.00:
$6.00y/$6.00 = $6.00/$6.00
y = 1
So the number of bags of walnuts he can buy is 1 bag.