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ludmilkaskok [199]
4 years ago
12

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
2 answers:
Ghella [55]4 years ago
8 0

Answer:

Graphing the points, the answer would be the reflection since you would see that they are reflections to the x-axis because all x coordinates are the same, but y coordinates transformed into negative. So, this will give us, Quadrilateral J K L M with the following vertices:J(8, 4), K(4, 10), L(12, 12), and M(14, 10) is congruent to quadrilateral WXYZ with the following vertices: W(8, -4), X(4, -10), Y(12, -12), and Z(14, -10).Since you only look for the reflection and not all the transformations are needed.

Step-by-step explanation:

Serga [27]4 years ago
7 0

Answer:

1. W(5,1),X(1,7),Y(9,9) and Z(11,7).

2.A(-8,-4),B(-4,-10),C(-12,-12) and D(-14,-10).

3. E(5,6) ,F(1,12),G(9,14) and H(11,12).

4.O(10,1),P(6,7),Q(14,9) and R(16,7).

Step-by-step explanation:

We are given that a quadrilateral JKLM with vertices J(8,4),K(4,10),L(12,12) and M(14,10)

We have to match a quadrilateral with its correct transformation of given quadrilateral JKLM

1.a transformation 3 units down and 3 units left

By using transformation rule (x,y)\rightarrow (x-3,y-3)

The new  vertices  of quadrilateral is (5,1), (1,7),(9,9) and (11,7).

Hence, the quadrilateral WXYZ with vertices W(5,1),X(1,7),Y(9,9) and Z(11,7).

2.A sequence of reflection across x- axis and y-axis in order

Reflection across x- axis

The transformation  rule (x,y)\rightarrow (x,-y)

By using this rule

The vertices of quadrilateral are  (8,-4),(4,-10),(12,-12) and (14,-10).

After the reflection across y- axis

The transformations rule

(x,y)\rightarrow (-x,y)

By using this rule

We get the new vertices of quadrilateral are (-8,-4),(-4,-10),(-12,-12) and (-14,-10).

Hence, the quadrilateral ABCD with vertices A(-8,-4),B(-4,-10),C(-12,-12) and D(-14,-10).

3.a translation 3 unit left and 2 units up

The transformation rule (x,y)\rightarrow (x-3,y+2)

By using this rule

The new vertices are (5,6),(1,12),(9,14) and (11,12).

Hence, the quadrilateral EFGH with vertices E(5,6) ,F(1,12),G(9,14) and H(11,12).

4.a translation 2 units right and 3 units down

The transformation rule

(x,y)\rightarrow (x+2,y-3)

By using this rule

The new vertices are (10,1),(6,7),(14,9) and (16,7)

Hence, the quadrilateral OPQR with vertices O(10,1),P(6,7),Q(14,9) and R(16,7).

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Estimate 38¼ - 14¾ by rounding each number to the nearest whole number.
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By rounding each number to the nearest whole number is  23.5

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1 year ago
At a certain coffee shop, all the customers buy a cup of coffee and some also buy a doughnut. The shop owner believes that the n
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Answer:

(1) The probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2) The shop owner has no reasonable chance to expect earning a profit more than $300.

(3) The probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

Step-by-step explanation:

Let <em>X</em> = number of cups of coffee sold and <em>Y</em> = number of donuts sold.

The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = 320 and <em>σ </em>= 20.

The random variable <em>Y</em> follows a Normal distribution with parameters <em>μ</em> = 150 and <em>σ </em>= 12.

The shop owner opens the shop 6 days a week.

(1)

Compute the probability that the shop owner sells over 2000 cups of coffee in a week as follows:

P(X>2000)=P(\frac{X-\mu}{\sigma}>\frac{2000-(6\times320)}{6\times20})\\=P(Z>0.67)\\=1-P(Z

Thus, the probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2)

The equation representing the profit earned on selling 1 cup of coffee and 1 doughnut in a day is:

P = 0.5<em>X</em> + 0.4<em>Y</em>

Compute the probability that the shop owner earns more than $300 as profit as follows:

P(Profit>300)=P(\frac{Profit-\mu}{\sigma}>\frac{300-((0.5\times320)+(0.4\times150))}{\sqrt{0.5^{2}(20)^{2}+0.4^{2}(12)^{2}}})\\=P(Z>7.21)\\\approx0

The probability of earning a profit more then $300 is approximately 0.

Thus, the shop owner has no reasonable chance to expect earning a profit more than $300.

(3)

The expression representing the statement "he'll sell a doughnut to more than half of his coffee customers" is:

<em>Y</em> > 0.5<em>X</em>

<em>Y</em> - 0.5<em>X</em> > 0

Compute the probability of the event (<em>Y</em> - 0.5<em>X</em> > 0) as follows:

P(Y - 0.5X > 0)=P(\frac{(Y - 0.5X) -\mu}{\sigma}>\frac{0-(150-(0.5\times320}{\sqrt{12^{2}+0.5^{2}20^{2}}})\\=P(Z>0.64)\\=1-P(Z

Thus, the probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

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Answer:

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Step-by-step explanation:

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