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ludmilkaskok [199]
4 years ago
12

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
2 answers:
Ghella [55]4 years ago
8 0

Answer:

Graphing the points, the answer would be the reflection since you would see that they are reflections to the x-axis because all x coordinates are the same, but y coordinates transformed into negative. So, this will give us, Quadrilateral J K L M with the following vertices:J(8, 4), K(4, 10), L(12, 12), and M(14, 10) is congruent to quadrilateral WXYZ with the following vertices: W(8, -4), X(4, -10), Y(12, -12), and Z(14, -10).Since you only look for the reflection and not all the transformations are needed.

Step-by-step explanation:

Serga [27]4 years ago
7 0

Answer:

1. W(5,1),X(1,7),Y(9,9) and Z(11,7).

2.A(-8,-4),B(-4,-10),C(-12,-12) and D(-14,-10).

3. E(5,6) ,F(1,12),G(9,14) and H(11,12).

4.O(10,1),P(6,7),Q(14,9) and R(16,7).

Step-by-step explanation:

We are given that a quadrilateral JKLM with vertices J(8,4),K(4,10),L(12,12) and M(14,10)

We have to match a quadrilateral with its correct transformation of given quadrilateral JKLM

1.a transformation 3 units down and 3 units left

By using transformation rule (x,y)\rightarrow (x-3,y-3)

The new  vertices  of quadrilateral is (5,1), (1,7),(9,9) and (11,7).

Hence, the quadrilateral WXYZ with vertices W(5,1),X(1,7),Y(9,9) and Z(11,7).

2.A sequence of reflection across x- axis and y-axis in order

Reflection across x- axis

The transformation  rule (x,y)\rightarrow (x,-y)

By using this rule

The vertices of quadrilateral are  (8,-4),(4,-10),(12,-12) and (14,-10).

After the reflection across y- axis

The transformations rule

(x,y)\rightarrow (-x,y)

By using this rule

We get the new vertices of quadrilateral are (-8,-4),(-4,-10),(-12,-12) and (-14,-10).

Hence, the quadrilateral ABCD with vertices A(-8,-4),B(-4,-10),C(-12,-12) and D(-14,-10).

3.a translation 3 unit left and 2 units up

The transformation rule (x,y)\rightarrow (x-3,y+2)

By using this rule

The new vertices are (5,6),(1,12),(9,14) and (11,12).

Hence, the quadrilateral EFGH with vertices E(5,6) ,F(1,12),G(9,14) and H(11,12).

4.a translation 2 units right and 3 units down

The transformation rule

(x,y)\rightarrow (x+2,y-3)

By using this rule

The new vertices are (10,1),(6,7),(14,9) and (16,7)

Hence, the quadrilateral OPQR with vertices O(10,1),P(6,7),Q(14,9) and R(16,7).

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Answer:

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4 years ago
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Step-by-step explanation:

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3 years ago
Make t the subject of the formula.<br><br> Please help.
Digiron [165]

Answer:

t = \frac{2-3q}{q+4}

Step-by-step explanation:

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5 0
3 years ago
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Now, we are given that triangle CDA is congruent to triangle XYZ.
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7 0
3 years ago
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