Question

A shelf holds 12 books in a row. How many ways are there to choose five books so that no two adjacent books are chosen

Answer 1

Answer:

792 ways

Step-by-step explanation:

We can solve this using the combination formular

$nCr= \frac{n!}{r!(n-r)!}$ where n represents the total number of objects/items, and r represents the number of items being chosen at a time.

Hence, in this case, n =  12, r = 5, which is = $nCr= \frac{12!}{5!(12-5)!}$ = 792.

Therefore, there are 792 ways to choose five books so that no two adjacent books are chosen.