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Masteriza [31]
3 years ago
14

A shelf holds 12 books in a row. How many ways are there to choose five books so that no two adjacent books are chosen

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

<u>792 ways</u>

Step-by-step explanation:

We can solve this using the combination formular

nCr= \frac{n!}{r!(n-r)!} where n represents the total number of objects/items, and r represents the number of items being chosen at a time.

Hence, in this case, n =  12, r = 5, which is = nCr= \frac{12!}{5!(12-5)!} = 792.

Therefore, there are 792 ways to choose five books so that no two adjacent books are chosen.

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