What is the inverse of the function
id="TexFormula1" title="a(x) = \frac{1}{x} - 2" alt="a(x) = \frac{1}{x} - 2" align="absmiddle" class="latex-formula">
2 answers:
a(x) = 1/x - 2
or
y = 1/x - 2
Switch x and y to find the inverse function
x = 1/y - 2
1/y = x + 2
y = 1 / (x + 2)
Answer
a^-1(x) = 1 / (x + 2)
To find the inverse, swap the x's and y's and solve for y. <em>Remember that a(x) represents y</em>
y =
- 2 <em>given</em>
x =
- 2 <em>x's and y's swapped</em>
x + 2 =
<em>added 2 to both sides</em>
y(x + 2) = 1 <em>multiplied y on both sides</em>
y =
divided (x + 2) on both sides
Answer:
=
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