50 POINTS please help me I really need it
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The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.
Given:
A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.
A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.
To find :
The scuba diver's position relative to sea level after the 4.6 minutes.
Solution:
Rate of a scuba diver descending in the water for 2.6 minutes =
Distance covered by a scuba diver in 2.6 minutes =
Rate of a scuba diver ascending for 2 minutes =
Distance covered by a scuba diver in 2 minutes =
The position of scuba diver after 4.6 minutes relative to sea level:
The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.
Learn more about ascending rate and descending rate here:
When you reflect a function in the <em>x</em>-axis, the first coordinate of a point stays the same, and the second coordinate changes sign (what was positive is now negative and vice versa). See the attached picture.
Question 11: f(x) = -5x + 2. The function changes to its opposite, so g(x) = -(-5x + 2) = 5x - 2.
When you reflect a function in the <em>y</em>-axis, the first coordinate of a point changes to its opposite, but the second coordinate stays the same. Replace <em>x</em> with -<em>x</em> .
Question 14: f(x) = |2x - 1| + 3. Replacing <em>x</em> with -<em>x</em> produces g(x) = |2(-x) - 1| + 3 which simplifies to g(x) = |-2x -1| + 3.
Question 15 works the same way as #14.
