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juin [17]
4 years ago
15

X/3 -13=18 Please help

Mathematics
2 answers:
Anestetic [448]4 years ago
8 0

Answer:

x=93

Step-by-step explanation:

Add 13 by both sides

x/3 - 13 + 13 = 18 + 13

simplify

x/3 =31

Multiply both sides by 3

3x/3=31 times 3

simplify

x= 93

RoseWind [281]4 years ago
5 0

Answer:

the answer is x=93

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70 minutes, you divide 420 by 6

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4 years ago
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-x=-24 <br> it’s for pre-algebra
labwork [276]
So -x can also represent -1

You want to divide both sides by -1 so you can get -x to be just x

-x divided by -1 = x
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Your answer is x=24
8 0
4 years ago
7 more than d is equal to 19
galben [10]

7+d=19 is the answer

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4 0
3 years ago
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Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
4 years ago
Hi! Please explain how you got the answer, thanks! :))​
disa [49]

Answer:

2000

Step-by-step explanation:

1996: 30+5 5×6=30

2000: 60+10 10×6=60

5 0
3 years ago
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