Answer:
Step-by-step explanation:
Volume = (l × w × h)/3
V = (15×20×15)/3
V = 1500cubic cm
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To extend that further, if the polygon has x sides, the sum, S, of the degree measures of these x interior sides is given by the formula S = (x - 2)(180).
For example, a triangle has 3 angles which add up to 180 degrees. A square has 4 angles which add up to 360 degrees. For every additional side you add, you have to add another 180 degrees to the total sum.
Quadrilateral ABCD has, of course, four angles. Those four angles are in the ratio 2:3:3:4. Find the degree measure of the biggest<span> angle of quadrilateral ABCD.</span>
Steps:<span>Add the terms 2x + 3x + 3x + 4xEquate the sum of the terms to 360Solve for xDetermine the angle measures in degrees.</span>Solve
2x + 3x + 3x + 4x = 360
12x = 360
x = 360/12
x = 30
Even though we know x = 30 we aren't done yet. We multiply 30 times 4 to find the biggest angle. Since 30 times 4 = 120, the biggest angle is 120 degrees. Likewise, the other angles are 3*30=90, 3*30=90, and 2*30 = 60.
Answer:
I think you have to multiple them all around the triangle
12/3=4
4 inches per 1/4 of the year.
4x4=16
Therefore it would grow 16 inches in an year.
Answer:
You'll have a <u>closed circle at x = 2</u>, and <u>shading to the left</u>
See the diagram below
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Explanation:
The fractions here are 3/7 and 21/2. The denominators of which are 7 and 2 respectively. The LCD is 7*2 = 14.
If we multiply both sides by 14, then this will clear out the denominators and make the fractions go away.
- 14*(3/7) = (14*3)/7 = 42/7 = 8
- 14*(21/2) = (14*21)/2 = 294/2 = 147
So if we multiplied both sides by 14, then we have these steps
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Let's isolate x
The graph of this will consist of a closed or filled in circle at x = 2. We shade to the left to represent numbers smaller than 2.
So either x = 2 or x < 2.
If we used an open hole at 2, then we wouldn't be including 2 (but we want to include this endpoint).
See the diagram below.