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NikAS [45]
3 years ago
10

What do solve 7,876x8

Mathematics
2 answers:
sladkih [1.3K]3 years ago
8 0
The answer is 63,008
natta225 [31]3 years ago
5 0
63,008 is your answer
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Craig used repeated addition to show 3 times 3/5. Which shows an expression Craig could write?
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3/5+3/5+3/5=9/5=1 4/5
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Putting soil is sold in bags that contain 1/2 cubic foot of soil. Estimate how many bags Rylee should buy.
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Ok. So, I can't see the image. Buttttt, depending on how many cubic feet she wants. If she wanted 5.5 cubic feet of soil, she would buy 10 bags of soil. Each showing 1/2 of a cubic foot. Use your fingers to help saying, " Half, One, One and a half, two, two and a half...." So on and so forth.

Step-by-step explanation:

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Use formulas to find the area of the figure. A triangle has a horizontal bottom side of length 8 centimeters and two sides of le
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3 years ago
Question 4 of 10
ludmilkaskok [199]

Answer:

Option C. 3√3

Step-by-step explanation:

Please see attached photo for brief explanation.

In the attached photo, we obtained the following:

Opposite = a

Adjacent = 3

Hypothenus = 6

Angle θ = 60°

We can obtain the value of 'a' as follow:

Tan θ = Opposite /Adjacent

Tan 60° = a/3

Cross multiply

a = 3 x Tan 60°

But: Tan 60° = √3

a = 3 x Tan 60°

a = 3 x √3

a = 3√3

Therefore, the length of the altitude of the equilateral triangle is 3√3.

5 0
3 years ago
The Surface Area of a square pyramid is 3600 ft. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot cu
amm1812

Answer:

10,583 flexible cubes

9915 rigid cubes

Step-by-step explanation:

The equation for the surface area of a square pyramid is area of base plus perimeter of base multiplied by the slant height

Surface area = A + 1/2·p·s

The volume of the pyramid = 1/3×A×h

Where:

A = Area of the base = 20 × 20 = 400 ft²

h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)

h = √(80² - (20/2)²) = 30·√7

The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³

If the cubes are flexible, approximately 10,583 cubes

For rigid cubes we have

Given that the height of the pyramid = 30·√7

The slope of the pyramid = 30·√7/10 = 3·√7

So an increase in height of 1 foot gives a reduction in width of 2/(3·√7)

The bottom can hold 400 cubes

The next layer can hold 19×19 = 361

3rd 361

4th 361

5th 324

6th 324

7th 324

8th 324

9th

Continuing, we get a total of about 9915 rigid cubes in the pyramid.

3 0
3 years ago
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