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Paraphin [41]
2 years ago
15

Given b(x)=|x+41|, what is b(-10)?

Mathematics
1 answer:
Montano1993 [528]2 years ago
6 0

Answer:

31

Step-by-step explanation:

Substitute -10 for x in b(x)=|x+41|, obtaining f(-10) = |-10 + 41|.  This result simplifies to f(-10) = |31| = 31

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Graph △XYZ with vertices X(2, 3), Y(−3, 2), and Z(−4,−3) and its image after the translation (x, y)→(x+3, y−1)
viktelen [127]

Answer:

  • X'(5, 2)
  • Y'(0, 1)
  • Z'(-1, -4)

Step-by-step explanation:

The translation increases each x-coordinate by 3, moving the point 3 units to the right. It decreases each y-coordinate by 1, moving the point 1 unit down.

  (x, y) ⇒ (x+3, y-1)

  X(2, 3) ⇒ X'(5, 2)

  Y(-3, 2) ⇒ Y'(0, 1)

  Z(-4, -3) ⇒ Z'(-1, -4)

The red arrows show the translation of each point in the graph.

5 0
4 years ago
What is m∠C?<br><br> Round the value to the nearest degree.
Elis [28]

Answer: m\angle C=53\°

Step-by-step explanation:

For this exercise you need to use the Inverse Trigonometric function arcsine, which is defined as the inverse function of the sine.

Then, to find an angle α, this is:

\alpha =arcsin(\frac{opposite}{hypotenuse})

In this case, you can identify that:

\alpha =m\angle C\\\\opposite=AB=36\ cm\\\\hypotenuse=AC=45\ cm

Then, substituting values into \alpha =arcsin(\frac{opposite}{hypotenuse}) and evaluating, you get that the measure of the angle "C" to the nearest degree, is:

m\angle C=arcsin(\frac{36\ cm}{45\ cm})\\\\m\angle C=53\°

5 0
3 years ago
What is the equation of the line that passes through the point (1,7) and is perpendicular to the graph of Y=-14X+11
vlada-n [284]
Y=1/14x might be the answer
4 0
3 years ago
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7 0
3 years ago
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vagabundo [1.1K]
He bought 5
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4 0
4 years ago
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