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Xelga [282]
4 years ago
5

What fraction of a metre is 40 centimetres

Mathematics
1 answer:
Reil [10]4 years ago
6 0

Step-by-step explanation:

4/10  or 2/5 *i'm sure :)

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ABCD is a rectangle with diagonals segment AC and segment BD. If AC = 2х + 10 and BD -=56, find the value of х." О23О33О 78 O 12
Aleks04 [339]

Answer:

Step-by-step explanation:

The diagonals of a rectangle are equal.

2x + 10 = 56         That minus sign can't be there. Subtract 10 from both sides.

2x  = 56 - 10         Combine

2x = 46                 Divide by 2

x = 46/2

x = 23

7 0
3 years ago
Points C and D lie on circle O as shown below. If OC = 6x+2 and OD = 10x -16, then find the length of the radius of circle O.
Ket [755]
Radius = OC = OD

Solve for x:

10x -16 = 6x+2

4x = 18

x = 9/2 = 4.5

Sub 'x' back into OC

OC = 6(4.5) + 2 = 29

Radius = 29
3 0
3 years ago
50 Points! find x and explain how you found it!
stepan [7]

To find the length of the side opposite the angle while knowing the hypotenuse we can use the sine function:

   sin(53) = (side opposite angle of 53 degrees) / hypotenuse

    sin(53) = x / 24

     x = 24 sin(53)

    x = 19.16

Hope that helped

3 0
2 years ago
Read 2 more answers
write the equation of a line that is parallel to the line described by x-4y=8. Explain how you know the lines are parallel. Plz
Gnoma [55]
If the lines have the same slope but different y-intercepts, then the lines are parallel.
8 0
3 years ago
Read 2 more answers
How do I solve this type of problem? I'm trying to find both missing values. Please explain how to solve this as thoroughly as y
goldenfox [79]
Hi there! 

In order to solve, we'll need to use a proportion: 20/a = 21/20. Then, we'll cross-multiply and solve to find a: 21a = 400 | a = 19.05. Next, to find b, we can just use pythagorean theorem: 20^2 + (400/21)^2 = b^2 | b = 27.62.
We are using geometric mean to solve for a, then using pythagorean theorem to solve for b. If you need more help with geometric mean, or would like a complete explanation, please let me know! I'd be happy to provide you with that information.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
3 0
3 years ago
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