12e^5 divide by 3e^3

Mathematics

1 answer:

Paladinen [302]3 years ago

5 0

The answer would be <em>29.5562243957</em>.

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stiv31 [10]

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Ming's DVD collection includes 16 adventures movies, 7 comedies, 12 westerns, and 8 mysteries. He wants to keep 8 of the DVDs an

alina1380 [7]

43 total movies the type of movies is added in to confuse you pay no ttention just add the total. he keeps 8 of them
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3 years ago

Caleb and Mike both score the same amount of points in a game. Caleb has fifteen less than the total number of points. Mike has

elena-s [515]

Answer:
129 points
Step-by-step explanation:
Let L and C represent the scores of Luke and Caleb, respectively.
L = 2C -15 . . . . . Luke scored 15 less than twice the number Caleb did
L +C = 201 . . . . . they scored 201 points altogether
Add twice the second equation to the first:
2(L +C) + (L) = 2(201) + (2C -15)
3L +2C = 387 +2C . . . . simplify
3L = 387 . . . . . . . . . . . . .subtract 2C
L = 387/3 = 129 . . . . . . .divide by 3
Luke scored 129 points.

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4 years ago

Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.

Ann [662]

Answer:

$Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686$

Step-by-step explanation:

$Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686$

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3 years ago

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Degger [83]

Answer:

Step-by-step explanation:

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3 years ago