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FromTheMoon [43]
2 years ago
5

One section of an atatoriwm has 12 rows each row has 13 seats what is the total number of seats in that section

Mathematics
1 answer:
daser333 [38]2 years ago
6 0

Answer:

156

Step-by-step explanation:

A problem like this can be solved using multiplication. If each row has 13 seats and there are 12 rows you can get the total amount of seats by multiplying 13x12.

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Find x- and y-intercepts. Write ordered pairs representing the points where the line crosses the axes. 2x+3y=6
sweet-ann [11.9K]

Answer:

x-intercept: (3, 0)

y-intercept: (0, 2)

Step-by-step explanation:

For a function like:

y = f(x)

The x-intercept is the value of x when y = 0

the y-intercept is the value of y when x = 0

Also remember that an ordered pair is written as (x, y).

In this case we have the equation:

2*x + 3*y = 6

For the x-intercept, we just replace y by zero in the equation, then we get:

2*x + 3*0 = 6

Solving this for x, we get:

2*x = 6

x = 6/2 = 3

Then in this case, the ordered pair for the x-intercept is (3, 0)

For the y-intercept, we just need to replace x by zero in the equation:

2*0 + 3*y = 6

Solving this for y, we get:

3*y = 6

y = 6/3 = 2

Then the ordered pair for the y-intercept is (0, 2)

8 0
3 years ago
Write the equation of the line that passes through the points (1, 1) and (2, 4). Write your answer in slope-intercept form
navik [9.2K]

Answer:

The answer in slope-intercept form is y = 3x - 2.

8 0
3 years ago
Solve the following equation. | x + 3 | = 4
Lelechka [254]

Answer:

x1= -7 , x2= 1

Step-by-step explanation:

8 0
3 years ago
Two angles are ____ when they have a common vertex and a common side and don’t overlap.
NISA [10]
Adjacent Angles<span> are </span>two angles<span> that share a </span>common vertex<span>, a </span>common side<span>, and no </span>common<span> interior points. (</span>They<span> share a </span>vertex<span> and </span>side<span>, but do not </span>overlap<span>.) A Linear Pair is </span>two<span> adjacent </span>angles<span> whose non-</span>common sides<span> form opposite rays

</span>
4 0
3 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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