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3 years ago

Can someone help ASAP ill give you good rating

Mathematics

2 answers:

masya89 [10]3 years ago

5 0

Answer: radius is is 12.

Step-by-step explanation:

Explanation: A circle with equation of the form x2+y2=r2 will have radius r=√144=12 .

Sorry, I'm not sure on the bottom part

kicyunya [14]3 years ago

4 0

<h2>Solution:-</h2>

We know,

The general equation for circle is –

${ \boxed{\bf{\rm \red {(x \: - \: a)² \: + \: (y \: - \: b)² \: = \: r²}}}}$

$\bf (a, \: b) \: = \: center \: coordinates$

$\bf r \: = \: radius$

$\bf a \: = \: 0 \: , \: b \: = \: 0 \: , \: r \: = \sqrt{144} \: = \: 12$

$\bf Center \: coordinates \: = \: (0, \: 0)$ [Answer]

$\bf Radius \: = \: 12$ [Answer]

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NOTE – Refer the above attachment.

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B2-4b+4=0 using quadratic forumla

Ivan

Trying to factor by splitting the middle term

Factoring b2-4b+4
The first term is, b2 its coefficient is 1 .
The middle term is, -4b its coefficient is -4 .
The last term, "the constant", is +4 

Step-1 : Multiply the coefficient of the first term by the constant 1 • 4 = 4

Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is -4 .

-4 + -1 = -5 -2 + -2 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
 b2 - 2b - 2b - 4

Step-4 : Add up the first 2 terms, pulling out like factors :
 b • (b-2)
 Add up the last 2 terms, pulling out common factors :
 2 • (b-2)
Step-5 : Add up the four terms of step 4 :
 (b-2) • (b-2)
 Which is the desired factorization

8 0

3 years ago

Read 2 more answers

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

3 years ago

Which expression shows 36 + 63 as the product of their greatest common factor and the sum of two whole numbers with no common fa

jarptica [38.1K]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~

The first thing we know is that all the answers equal 99, so we cannot cross any answer off, however, what we want to know is what answer (after distribution) looks like 36 + 63...

A.) 11(3 + 6) > 33 + 66

Does 33+66 look like 36+63?

B.) 9(4 + 7) > 36 + 63

Does 36+63 look like 36+63?

YES

C.) 11(4 + 5) > 44 + 55

Does 44+55 look like 36+63?

D.) 3(15 + 18) > 45 + 54

Does 45+54 look like 36+63?

So...

The answer is: B.) 9(4 + 7)

4 0

3 years ago

Given RT below, if S lies on RT such that the ratio of RS to ST is 3:1, find the coordinates of S.

Ksivusya [100]

Answer:

S(-2, -3)

Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

X = -8/4

X = -2

Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4

Y = -12/4

Y = -3

Hence the coordinate of the point (X, Y) is (-2, -3)

5 0

3 years ago

If ABC is reflected across the y-axis, what are the coordinates of A?

quester [9]

Answer:

The answer is option A

Step-by-step explanation:

Reflection in the y axis is

(x , y) → ( - x , y)

The coordinates of A are ( 2, -5)

When it's reflected in the y axis it becomes

( - 2 , - 5)

Hope this helps you

4 0

3 years ago