The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
<h3>Ratio of the areas of similar figures </h3>
From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>
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The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be



= 4:1
Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446
Answer:LOL 26
Step-by-step explanation: 22=4 IS LIKE EASY BUT IF YOU FORGOT THEN THATS FINE
Y=3x2+1
Hope this helped :)
Answer:
$1.56
Step-by-step explanation:
125.32 : 80.5 = 1.55677 => ~1.56$
The formula for a quadratic function is y=ax^2+bx+c.
The vertex is h, k. This can be found by evaluating y to get k, and dividung -b by a in order to get h.
Hope this helps!