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tangare [24]
4 years ago
8

What is the length of side PQ?

Mathematics
1 answer:
barxatty [35]4 years ago
5 0
Okay, i can do this. But i need the graph 
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Simplify <br> 4(1 + 9x) thank you
Rufina [12.5K]

Answer:

4+36x

Step-by-step explanation:

you multiply the number on the outside of the parentheses with the numbers in the inside of the parentheses.

4 times 1 = 4

4 times 9x = 36x

36x+4

7 0
3 years ago
A rectangle has an area of 183.6 square miles and a base of 10.2 miles. What is the height?
aalyn [17]
18 miles

183.6 divided by 10.2 = 18, and to check the answer if we multiply 18 and 10.2 it equals 183.6
3 0
3 years ago
The area of a rectangle is 72cm square. Length,/, of the rectangle is 6 cm longer than the width w
Butoxors [25]
As you haven't specifically stated what exactly the question is, I will be assuming that the question is most likely asking for what the dimensions ( length and width ) of the rectangle is. With this in mind, I will be answering the question so here I go...


STEP-BY-STEP SOLUTION:

Let's solve this problem step-by-step.

Let's first establish the formula for the area of a rectangle as displayed below:

Area = Length × Width

A = lw

From this, we will establish the values for each of the parts in the area formula using the information given in the problem as displayed below:

A = 72cm^2

l = w + 6

w = w

Now, we will substitute these values into the area formula and then make ( w ) the subject as displayed below:

A = lw

72 = ( w + 6 ) ( w )

72 = w ( w + 6 )

72 = w^2 + 6w

0 = w^2 + 6w - 72

0 = w^2 + 12w - 6w - 72

0 = w ( w + 12 ) - 6 ( w + 12 )

0 = ( w + 12 ) ( w - 6 )


w + 12 = 0

w = 0 - 12

w = - 12


w - 6 = 0

w = 0 + 6

w = 6

As the answer must be positive as measurements are always positive, the answer must be the option which is a positive number.

Therefore:

w = 6

Using the equation we made for the length before, we can substitute the value of ( w ) to obtain the value of the length as displayed below:

l = w + 6

l = ( 6 ) + 6

l = 12


FINAL ANSWER:

The dimensions of the rectangle are:

Length = 12cm

Width = 6cm


Please mark as brainliest if this was helpful! : )
Thank you <3
7 0
4 years ago
536wiy3i6qjekuy4kerul4eluyk u4ledlure7l 6re.lel,u67e4 lerld,heyke l6e4df
11111nata11111 [884]
Well since "536wiy3i6q-----------" I can conclude that jncijenvjovnfouebfuasnokmnjbht6(yyy7ihhiswcnjiwdnjyudwucwdu=nonsense
7 0
3 years ago
Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6
musickatia [10]

Answer:

(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

Step-by-step explanation:

In order to find the values of (x+y)^5 and (x+y)^6, you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

(x+y)^5 = \sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i = \frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5 = x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5.

(x+y)^6 = \sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i = \frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6= x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6.

5 0
3 years ago
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