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4 years ago

15

-3x +5(x + 3) = 4 + 3x + 7(x - 6) into a simplified sentence

2 answers:

nydimaria [60]4 years ago

7 0

Answer:

-3x+5(x+3)=4+3x+7(x-6)

We move all terms to the left:

-3x+5(x+3)-(4+3x+7(x-6))=0

We multiply parentheses

-3x+5x-(4+3x+7(x-6))+15=0

We calculate terms in parentheses: -(4+3x+7(x-6)), so:

4+3x+7(x-6)

determiningTheFunctionDomain
3x+7(x-6)+4

We multiply parentheses

3x+7x-42+4

We add all the numbers together, and all the variables

10x-38

Back to the equation:

-(10x-38)

We add all the numbers together, and all the variables

2x-(10x-38)+15=0

We get rid of parentheses

2x-10x+38+15=0

We add all the numbers together, and all the variables

-8x+53=0

We move all terms containing x to the left, all other terms to the right

-8x=-53

x=-53/-8

BartSMP [9]4 years ago

4 0

Answer:

2x+15=11x-38

Step-by-step explanation:

-3x+5(x+3)=4+3x+7(x-6) (first do the parentheses)

-3x+5x+15=4+3x+7x-42 (then add the common terms)

2x+15=11x-38

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Question 5 of 6Which values are equivalent to the fraction below? Check all that apply.11.В.A.31 1c.33OF 3-3

lys-0071 [83]

The question is given to be:

$\frac{3^5}{3^8}$

Applying the law of indices:

$\frac{a^m}{a^n}=a^{m-n}$

Therefore, we have the expression to be:

$\frac{3^5}{3^8}=3^{5-8}=3^{-3}$

Recall the law of negative exponents:

$a^{-m}=\frac{1}{a^m}$

Therefore, the expression becomes:

$3^{-3}=\frac{1}{3^3}=\frac{1}{3\times3\times3}=\frac{1}{27}$

The expression is also equivalent to:

$(\frac{1}{3})^3$

Since:

$(\frac{1}{3})^3=\frac{1^3}{3^3}=\frac{1}{27}$

ANSWER

The correct options are OPTION C, OPTION E, and OPTION F.

5 0

2 years ago

In Mrs. Kelly's class, 1/5 of the students failed the math test. Of the remaining students in the class, 1/4 scored an A. What f

masya89 [10]

Answer:
11/20

Explanation:
1/5 + 1/4
= 4/20 + 5/20
= 9/20

20/20 - 9/20 = 11/20

5 0

3 years ago

More Geometry Homework,<br> Can anyone help me?

jolli1 [7]

First one is 72 the second one is 20 the third one is 12 I can’t really see it so good luck

3 0

3 years ago

Pls help I made it 50 POINTS PLS HELP MEEE

barxatty [35]

Answer:

no 1 is true

Step-by-step explanation:

no2 also true. thank you

5 0

3 years ago

Read 2 more answers

Can someone help me with this? I'm not sure what I'm doing wrong, there are 3 rectangles and 2 triangles, I calculated them corr

yaroslaw [1]

Triangular case:-

B=9cm
H=6cm

$\\ \bullet\sf\leadsto Area=\dfrac{1}{2}BH$

$\\ \bullet\sf\leadsto Area=\dfrac{1}{2}(6)(9)$

$\\ \bullet\sf\leadsto Area=3(9)$

$\\ \bullet\sf\leadsto Area=27cm^2$

Area of both triangular sides=27+27=54cm^2

Rectangular case;-

L=7cm
B=5cm

$\\ \bullet\sf\leadsto Area=LB$

$\\ \bullet\sf\leadsto Area=7(5)$

$\\ \bullet\sf\leadsto Area=35cm^2$

Area of 3sides=35(3)=105cm^2

Now

$\\ \bullet\sf\leadsto TSA=105+54=159cm^2$

5 0

3 years ago