Find the difference vertically 2⁴⁄₉- 1⅐

Mathematics

2 answers:

Slav-nsk [51]2 years ago

6 0

Answer:

Step-by-step explanation:y’all goofy asl

V125BC [204]2 years ago

3 0

Answer:

$1 \frac{1}{7}$

Step-by-step explanation:

$2 \frac{4}{9} - 1 \frac{1}{7} \\ \frac{22}{9} - \frac{8}{7} \\ \frac{22 \times 7}{9 \times 7} - \frac{8 \times 9}{7 \times 9} \\ \frac{144 - 72}{63} \\ \frac{72}{63} \\ 1 \frac{9}{63} \\ 1 \frac{1}{7}$

hope this helps

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Sienna used the scale drawing above to create a pool that is 14 ft wide x 22 ft long. She then decided to make pool with a final

Bond [772]

A scale factor allows a shape to be changes into another shape by changing the linear dimensions to the multiples of the initial dimension and a constant

The expression that finds the change in scale factor for the longer pool with a final length of 33 ft. Sierra is building is the option;

$\dfrac{2 \, ft.}{3 \, ft.}$

Reason:

Known parameters are;

Dimensions of the pool created = 14 ft. wide × 22 ft. long

Final length of the pool = 33 ft.

Let x represent the length of the drawing using the initial scale factor, we have;

$The \ initial \ scale \ factor = \dfrac{22 \, ft.}{x \, in.}$

The scale factor of the drawing following a final length of 33 ft. is therefore;

$New \ scale \ factor = \dfrac{33 \, ft.}{x \, in.}$

The change in scale factor is given as follows;

$Change \ in \ scale \ factor = \dfrac{Initial \, scale \, factor}{Final \, scale \, factor}$

Therefore;

$Change \ in \ scale \ factor = \frac{\left( \dfrac{22 \, ft.}{x \, in.} \right)}{\left( \dfrac{33 \, ft.}{x \, in.} \right)} = \dfrac{2 \, ft.}{3 \, ft.}$