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Serga [27]
3 years ago
11

Given the sample triangle below and the conditions , find the hypotenuse of the triangle

Mathematics
1 answer:
alukav5142 [94]3 years ago
6 0
<span>ind the square root of c2.</span><span> Use the square root function on your calculator (or your memory of the multiplication table) to find the square root of c</span>2. The answer is the length of your hypotenuse!<span>In our example, <span>c2 = 25</span>. The square root of 25 is 5 (5 x 5 = 25, so Sqrt(25) = 5). That means c = 5, the length of our hypotenuse!</span> The Pythagorean Theorem describes the relationship between the sides of a right triangle.<span> It states that for any right triangle with sides of length a and b, and hypotenuse of length c, </span><span>a2 + b2 = c2


</span>Make sure that your triangle is a right triangle.<span> The Pythagorean Theorem only works on right triangles, and by definition only right triangles can have a hypotenuse. If your triangle contains one angle that is exactly 90 degrees, it is a right triangle and you can proceed.</span><span>Right angles are often notated in textbooks and on tests with a small square in the corner of the angle. This special mark means "90 degrees."
</span><span>

</span>Assign variables a, b, and c to the sides of your triangle.<span> The variable "c" will always be assigned to the hypotenuse, or longest side. Choose one of the other sides to be </span>a,<span> and call the other side </span>b<span> (it doesn't matter which is which; the math will turn out the same). Then copy the lengths of a and b into the formula, according to the following example:</span><span>If your triangle has sides of 3 and 4, and you have assigned letters to those sides such that a = 3 and b = 4, then you should write your equation out as: <span>32 + 42 = c2</span>.
</span>
Find the squares of a and b.<span> To find the square of a number, you simply multiply the number by itself, so </span><span>a2 = a x a</span>. Find the squares of both a and b, and write them into your formula.<span><span>If a = 3, a2 = 3 x 3, or 9. If b = 4, then b2 = 4 x 4, or 16.</span><span>When you plug those values into your equation, it should now look like this: <span>9 + 16 = c2</span>.
</span></span>


<span>Add together the values of <span>a2</span> and <span>b2</span>.</span><span> Enter this into your equation, and this will give you the value for c</span>2. There is only one step left to go, and you will have that hypotenuse solved!<span>In our example, 9 + 16 = 25, so you should write down <span>25 = c2</span>.

</span>
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a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s
Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

                         P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s^{2}  = sample variance = 97^{2} = 9409

              n = sample of boxes = 15

           \sigma^{2}  = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, \sigma^{2} is ;

P(5.629 < \chi^{2}__1_4 < 26.12) = 0.95  {As the critical value of chi-square at 14

                                         degree of freedom are 5.629 & 26.12}  

P(5.629 < \frac{(n-1)s^{2} }{\sigma^{2} } < 26.12) = 0.95

P( \frac{5.629 }{(n-1)s^{2} } < \frac{1}{\sigma^{2} } < \frac{26.12 }{(n-1)s^{2} } ) = 0.95

P( \frac{(n-1)s^{2} }{26.12 } < \sigma^{2} < \frac{(n-1)s^{2} }{5.629 } ) = 0.95

<u><em>95% confidence interval for</em></u> \sigma^{2} = [ \frac{(n-1)s^{2} }{26.12 } , \frac{(n-1)s^{2} }{5.629 } ]

                                                  = [ \frac{14 \times 9409 }{26.12 } , \frac{14 \times 9409 }{5.629 } ]

                                                  = [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

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