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3 years ago

Which relation is NOT a function?

Mathematics

1 answer:

Alina [70]3 years ago

4 0

B pretty sure hope this helps

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Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

3 0

3 years ago

Perform the operation. (10x2 – 10x – 6) + (x+6)

ivann1987 [24]

Answer:

10x² - 9x

Step-by-step explanation:

(10x² - 10x - 6) + (x + 6)

10x² - 10x - 6 + x + 6

10x² - 9x - 6 + 6

10x² - 9x

8 0

3 years ago

Which is a solution to the equation y equals 3x + 1 ?

Nata [24]

It is a, if you plug it in, it works. 10=3*3+1 is true.

7 0

3 years ago

Samuel already has 56 flowers in his garden, and he can also grow 1 flower with every seed packet he uses. How many seed packets

AveGali [126]

Answer:

Step-by-step explanation:

he will need that many because if you subtract 56 from 62 you will get 6 and you need one packet per flower so.. yea. 6

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3 years ago

2x = 6+ (-18)<br> I need the answer

JulijaS [17]

Answer:

x= -6

Step-by-step explanation

1: subtract

2: divide

3: simplify

7 0

3 years ago