Answer:
Step-by-step explanation:
<u>Firstly, we'll do prime factorization of these numbers.</u>
70 = 2 × 5 × 7
112 = 2 × 2 × 2 × 2 × 7
<u>So, The Greatest Common Factor can be written as:</u>
GCF = 2 × 7 <u>[Since Only one 2 and one 7 is common]</u>
<u></u>
Hope this helped!
<h2>~AnonymousHelper1807</h2>
I'll try to understand this but I don't really get it because I'm in middle school
Answer:
A, B, C
Step-by-step explanation:
Got it right on khan academy
Answer:
Both plans are correct
Step-by-step explanation:
I already did it
Answer:
- digits used once: 12
- repeated digits: 128
Step-by-step explanation:
In order for a number to be divisible by 4, its last two digits must be divisible by 4. This will be the case if either of these conditions holds:
- the ones digit is an even multiple of 2, and the tens digit is even
- the ones digit is an odd multiple of 2, and the tens digit is odd.
We must count the ways these conditions can be met with the given digits.
__
Since we only have even numbers to work with, the ones digit must be an even multiple of 2: 4 or 8. (The tens digit cannot be odd.) The digits 4 and 8 comprise half of the available digits, so half of all possible numbers made from these digits will be divisible by 4.
<h3>digits used once</h3>
If the numbers must use each digit exactly once, there will be 4! = 24 of them. 24/2 = 12 of these 4-digit numbers will be divisible by 4.
<h3>repeated digits</h3>
Each of the four digits can have any of four values, so there will be 4^4 = 256 possible 4-digit numbers. Of these, 256/2 = 128 will be divisible by 4.
