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2 years ago

The solution is an ordered pair and I can’t figure it out.

Mathematics

1 answer:

trasher [3.6K]2 years ago

7 0

The answer is -8 because if you do the math

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Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 m

dedylja [7]

Answer:

18.95%

Step-by-step explanation:

In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.

We know that there are 20 in total and that initially there are 9 jelly treats, so the first event is the probability:

9/20

And the second event, with one less in each, would be:

8/19

The final probability then:

9/20 * 8/19 = 0.1895

So the probability of this happening is 18.95%

4 0

3 years ago

Read 2 more answers

5 times 3 and 5 over 8 times 9 and 1 over 4

Ber [7]

The answer should be:
20.875

Hope this helps.

3 0

2 years ago

Read 2 more answers

What is the equation of the following line? be sure to scroll down first to see all answer options

andreyandreev [35.5K]

Answer:

The equation for the following graph:

$y = -\frac{1}{5}x$

Step-by-step explanation:

- You first need to find the slope by using the slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

(where $(x_{1},y_{1})$ is the first point and $(x_{2}, y_{2})$ is the second point)

-Use the given points $(0,0)$ and $(10, -2)$ from the graph for the formula:

$m = \frac{-2 - 0}{10 - 0}$

Then, you solve:

$m = \frac{-2 - 0}{10 - 0}$

$m = -\frac{1}{5}$

After you have found the slope, use the slope $-\frac{1}{5}$ and the first point $(0,0)$ for the point-slope formula:

$y - y_{1} = m ( x - x_{1})$

(where $m$ is the slope and $(x_{1}, y_{1})$ is the first point)

$y - 0 = -\frac{1}{5} ( x - 0)$

Then, you solve:

$y - 0 = -\frac{1}{5} ( x - 0)$

$y - 0 = -\frac{1}{5}x - 0$

$y - 0 + 0 = -\frac{1}{5} - 0 + 0$

$y = -\frac{1}{5}x$

So, the equation for the following graph is $y = -\frac{1}{5}x$ .

7 0

2 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

3 years ago

What is the approximate area of the following circle?

balu736 [363]

Answer:

$38.47 {m}^{2}$