Assuming a normal distribution we find the standardized z scores for a:-
z1 = (80 - 180) / 25 = = -100/25 = -4
z2 = (280-180) / 25 = 4
Required P( -4 < z < 4) from the tables is >99.9%
b
z1 = 130-180 / 25 = -2
z2 = 230-180 / 25 = 2
from tables probability is 2* 0.4773 = 95.46 %
-3p^3 + 5p -2p^2 - 4 - 12p + 5 + 8p^3
5p^3 - 2p^2 - 7p + 1
It is the second choice
About 5 books have been signed out, so they still have 4.
Answer:
-64
Step-by-step explanation:
I just simplify the like terms to make it easier visually. After that, I plugged in j and k and solve for the answer which is -64.
C. 55%
The crusaders won 55% of 20 games
