Answer:
C. (1, 10) and (6, 5)
Step-by-step explanation:
To find the point with a distance of 5 units.
Let the points be x and y.
x = x1 and x2
y = y1 and y2
x2 - x1 = 5 units
y2 - y1 = 5 units.
A quick look at the options, we can tell that the correct option is C.
From points (1, 10) and (6, 5)
x1 = 1, x2 = 6, y1 = 10 and y2 = 5
Substituting into the equation above, we have;
x2 - x1 = 6 - 1 = 5 units
y2 - y1 = 5 - 10 = -5 units.
Therefore, option C with points (1,10) and (6,5) have a distance of five units between them.
Answer:
-200.5
Step-by-step explanation:
that’s just the right answer lol
An expression becomes an equation by adding an equal sign to the end of the expression and if there's a number on the other side of the equation. For example, 4+3 becomes an equation if you put 4+3=7. Or, 4+3=2+5. Good luck!
The answer would be as follows:
(s+t)(x) = s(x)+t(x)
So:
(s+t)(x) = (x+6)+(3x+2)
Simplify:
(s+t)(x) = 4x+8
