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yanalaym [24]
3 years ago
10

Write the equation of the line parallel to 5x + y = -2 that goes through the point (2, -3).

Mathematics
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

y = -5x + 7

Step-by-step explanation:

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Find the zeros of the function. State the multiplicity of any multiple zeros.
Vadim26 [7]

Hi,

Pretty simple: if a result of a multiplication is equal to 0, then each factor is equal to 0.

y = f(x) = (x -- 5)(x + 2)² = 0, so:

x₁ -- 5 = 0 ⇒ x₁ = 5.

(x + 2)² = 0 ⇒ x₂ = x₃ = --2, for --2 we have state of multiplicity = 2.

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the graph of F(x), shown below, has the same shape as the graph of G(x)=x^2. but it is shifted up 4 units and to the right 2 uni
ale4655 [162]

Answer:

Step-by-step explanation:

The graph of y=x^2 in vertex form is y=(x-h)^2+k where h and k, the vertex, is (0, 0). If we shift the parabola right or left, or up or down, the h and k values take on that reflection. If we move up 4, k goes from a value of 0 to a value of 4; if we move right 2 units, h goes from a value of 0 to a value of 2. Putting that together in work (aka vertex) form:

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Solve for x using cross multiplication 3x - 3 5 = 2x – 2 4 x = [?]​
Harlamova29_29 [7]

Answer:

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Step-by-step explanation:

Solving for x will be easy enough, but cross multiplication won't be necessary as that's only applicable when division is involved:

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35 = -22x

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The sum of two numbers is 17 and their difference is 5. What are the two numbers?
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Should be 11 and 6 because when you add 11 and 6 you get 17 and when you subtract them you get 5
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