Question

the graph of F(x), shown below, has the same shape as the graph of G(x)=x^2. but it is shifted up 4 units and to the right 2 units. What is its equation

Answer 1

Answer:

Step-by-step explanation:

The graph of $y=x^2$ in vertex form is $y=(x-h)^2+k$ where h and k, the vertex, is (0, 0). If we shift the parabola right or left, or up or down, the h and k values take on that reflection. If we move up 4, k goes from a value of 0 to a value of 4; if we move right 2 units, h goes from a value of 0 to a value of 2. Putting that together in work (aka vertex) form:

$y=(x-2)^2+4$