Question

b ^{2} + 4b - 4" alt="a^{2} - b ^{2} + 4b - 4" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$\left(a+b-2\right)\left(a-b+2\right)$

Step-by-step explanation:

$a^2-b^2+4b-4$

$a^2-\left(b^2-4b+4\right)$

$a^2-(b^2-2b-2b+4)$

$a^2-\left(b-2\right)\left(b-2\right)$

$a^2-\left(b-2\right)^2$

Apply the difference of two squares formula.

$x^2-y^2=(x+y)(x-y)$

$\left(a+\left(b-2\right)\right)\left(a-\left(b-2\right)\right)$

$\left(a+b-2\right)\left(a+2-b\right)$