3 years ago

Im doing a test review and I have no idea how to do this

Mathematics

1 answer:

Arisa [49]3 years ago

6 0

Answer:

94.3?

Step-by-step explanation:

Well, the straight line is 180 degrees, there is a 90 degree square, and a 13 degree angle. So add them up and divide by three?

You might be interested in

A fenced-in rectangular area has a perimeter of 40 ft. The fence has a post every 5 ft.

sertanlavr [38]

8 post 4ft is the length 2ft ,yes if you dived 5 from 40 that is how many post , then you dived how many posts and that is the height then you dvide that and that is your width.

7 0

2 years ago

The graph shows the relationship between time

rusak2 [61]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

a regular square pyramid just fits inside a cube (the base of the pyramid is congruent to a face of the cube and the height of t

Tom [10]

The answer is larger in volume because the come is holow in the inside and that square pyrimid isn't

3 0

3 years ago

HELP ME PLEASE IM BEGGING

agasfer [191]

95 is the area
Hope this helps :p

8 0

2 years ago

Read 2 more answers

Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

8 0

2 years ago

Im doing a test review and I have no idea how to do this​

Im doing a test review and I have no idea how to do this