Answer:
30
Step-by-step explanation:
Since the question says that it took her 45 minutes per hour, you can use that to find the distance of the route she took.
45 miles: 60 minutes
15 miles: 20 minutes ----------------cross multiply (20x45 and then divide by 60)
Therefore, if she is going to use the same route in reverse, the distance would be 15 miles.
Use the formula for speed:
speed= distance/time
= 15/0.5 ---------- 0.5 hours is the same as 30 minutes
= 30
Answer:
See below ↓↓
Step-by-step explanation:
<u>Equation of line k</u>
- y = mx + b
- m = Δy/Δx (ratio of change in y to change in x) = 2/3
- b = 3 (as y-intercept is [0,3])
- ⇒ y = 2/3x + 3
<u />
<u>a. parallel line</u>
- For parallel lines, slope (m) remains the same, but the y-intercept (b) changes
- ⇒ <u>y = 2/3x + 1</u>
<u></u>
<u>b. perpendicular line</u>
- For perpendicular lines, the slope (m) is the negative reciprocal of the original line and the value of b stays the same [it can be any point as long as it intersects the line]
- ⇒ <u>y = -3/2x + 1</u>
I assume the question asks to expand the expression to individual terms.
There are different ways to approach this, all based on FOIL or similar methods.
I prefer to split it into two parts, as follows:
(x+y+2)(y+1)
=x(y+1)+(y+2)(y+1)
=xy+x+y^2+3y+2
Answer:
○![\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B3%7D%5C%3A%5Bor%5C%3A-%5Cfrac%7B2%7D%7B%5Csqrt%7B3%7D%7D%5D)
Step-by-step explanation:
You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of 
which gives you 
Extended Information
![\displaystyle -\frac{2\sqrt{3}}{3} = [-\frac{\sqrt{3}}{2}]^{-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B3%7D%20%3D%20%5B-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5D%5E%7B-1%7D)
I am joyous to assist you anytime.
