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anzhelika [568]
3 years ago
15

Adult tickets to a basketball game cost 5$. Student tickets cost 1$. A total of 2,874$ was collected on the sale of 1,246. How m

any of each type of ticket were sold?
Mathematics
1 answer:
Karolina [17]3 years ago
8 0
2,874 divided by 5 = 574.8
Since we know anything divided by 1 is that number.
We do 2,874 - 574.8 = 2,299.2
This is how we get our answer.

So,574.8 of the 1,246 tickets were Adult tickets and 2,299.2 tickets were student tickets.
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3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

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From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

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\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

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Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
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