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anzhelika [568]
3 years ago
15

Adult tickets to a basketball game cost 5$. Student tickets cost 1$. A total of 2,874$ was collected on the sale of 1,246. How m

any of each type of ticket were sold?
Mathematics
1 answer:
Karolina [17]3 years ago
8 0
2,874 divided by 5 = 574.8
Since we know anything divided by 1 is that number.
We do 2,874 - 574.8 = 2,299.2
This is how we get our answer.

So,574.8 of the 1,246 tickets were Adult tickets and 2,299.2 tickets were student tickets.
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11.25 - 10.5 = 0.75

Knowing that this is the profit she makes with one share, so:

20 * 0.75 = 15

Caroline made $15 profit.

7 0
3 years ago
Suppose that 40 deer are introduced in a protected wilderness area. The population of the herd
Scorpion4ik [409]

The horizontal asymptote of the function is the minimum number of deer in the area.

  • The equation of horizontal asymptote is: \mathbf{y = 40}
  • The horizontal asymptote means that, the number of deer will never be less than 40

The equation is given as:

\mathbf{f(x) = \frac{40 + 2x}{1 + 0.05x}}

Expand the numerator

\mathbf{f(x) = \frac{40(1 + 0.05x)}{1 + 0.05x}}

Cancel out the common factor

\mathbf{f(x) = 40}

Hence, the equation of horizontal asymptote is:

\mathbf{y = 40}

The horizontal asymptote means that, the number of deer will never be less than 40

Read more about horizontal asymptotes at:

brainly.com/question/4084552

8 0
2 years ago
Graph the line that passes through the points ( 0 , − 4) and (−5,2) and determine the equation of the line.
Eduardwww [97]
  1. Answer:

i am highly sorry but there is no graph for me to help you with on this site :(

but to help you the X line always comes first for example the (-5,2) the -5 would be on the X line. I really hope that this help. :)

7 0
3 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
photoshop1234 [79]

Answer: 0.1353

Step-by-step explanation:

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Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that the instrument does not fail in an 8-hour shift :-

P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0
3 years ago
CAN I GET HELP ON THIS PLEASE WILL GIVE 5 STARS
nikklg [1K]

Answer:

I don't know the ans please search on the Google you will get

And don't forget to mark me as brainlest please guys and follow me back please please

6 0
3 years ago
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